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natta225 [31]
3 years ago
9

Which graph correctly matches the equation y = 2-x?

Mathematics
2 answers:
irga5000 [103]3 years ago
5 0

Answer:

The second one

Step-by-step explanation:

nalin [4]3 years ago
4 0

Answer:  The answer is attached in the figure.


Step-by-step explanation:  Given are four different graphs and we are to check which one matches with the equation y = 2 - x.

We have the following points on this equation.

(0,2), (1,1), (2,0), etc.

When we try to match these points with the given graphs, the we see that these points does not match with the first, third and fourth graph. The only graph containing these points is second one.

Thus, the second option is correct. Also see the attached figure for the location of the three mentioned points.


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stellarik [79]

Answer:

Perimeter of ΔABC: \frac{27}{2} + \frac{9}{2} * \sqrt6 units

Area of ΔABC: \frac{81}{8}*\sqrt3 + \frac{243}{8} units

<u>Skills required: HS Geo, Special Triangles</u>

Step-by-step explanation:

1) The best option is to break down this triangle. Let's draw an altitude from Point B down to Segment AC. The point from the altitude that intersects AC is Point D. BD is the height of our triangle, AC is the base.

2) Angle A is 60 degrees, and since Angle BDA is 90 degrees, Angle ABD is 30 degrees. We can use the 30-60-90 degree right triangle property for the triangle BDA.

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AB is 9 units, and it is opposite the 90 degree angle. This means that 2x=9, x = \frac{9}{2} ==> This then means that AD, the segment opposite the 30 degree angle in this triangle is \frac{9}{2} units. Segment BD (the height) is \frac{9}{2} * \sqrt3.

3) Angle C is 45 degrees, and Angle BDC is 90 degrees, which means that Angle CBD is 45 degrees. We can use the 45-45-90 degree right triangle property for the triangle BCD.

  • This states that if the side opposite the 45 degree angle is x, the other side opposite a 45 degree angle is also x, but the hypotenuse (side opposite the right (90 degree) angle) is \sqrt{2}*x.

BD is \frac{9}{2} * \sqrt3, which means DC is the same. BC, which is the hypotenuse is BD multiplied by square-root-2, which is \frac{9}{2} * \sqrt6.

4) Area is \frac{1}{2}*b*h, the base (b) is AC (which is \frac{9}{2}+\frac{9}{2}*\sqrt3), the height is BD (\frac{9}{2}*\sqrt3). When multiple you will get \frac{81}{4}*\sqrt3 + \frac{243}{4}, then this multiplied by 1/2 is

\frac{81}{8}*\sqrt3 + \frac{243}{8} <--> this is the area!

5) Perimeter is just the sum of all side: 9 + \frac{9}{2} + \frac{9}{2} * \sqrt6 = \frac{27}{2} + \frac{9}{2} * \sqrt6 unit

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3 years ago
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Rzqust [24]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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