Carlos ran the farthest at 7/10 of a mile because 7/10 is the largest fraction.
<h3>
Answer: n = -11</h3>
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Explanation:
Since x-2 is a factor of f(x), this means f(2) = 0.
More generally, if x-k is a factor of p(x), then p(k) = 0. This is a special case of the remainder theorem.
So if we plugged x = 2 into f(x), we'd get
f(x) = x^3+x^2+nx+10
f(2) = 2^3+2^2+n(2)+10
f(2) = 8+4+2n+10
f(2) = 2n+22
Set this equal to 0 and solve for n
2n+22 = 0
2n = -22
n = -22/2
n = -11 is the answer
Therefore, x-2 is a factor of f(x) = x^3+x^2-11x+10
Plug x = 2 into that updated f(x) function to find....
f(x) = x^3+x^2-11x+10
f(2) = 2^3+2^2-11(2)+10
f(2) = 8+4-22+10
f(2) = 0
Which confirms our answer.
Answer:
Sajini = 200
Drea = 225
Step-by-step explanation:
d = amount Drea earned
s = amount Sajini earned
Together they earned 425
d+s =425
d = s+25
The system of equations
d+s =425
d = s+25
I will use substitution to solve
Substitute d= s+25 into the first equation
d+s =425
(s+25) + s = 425
Combine like terms
2s+25 =425
Subtract 25 from each side
2s+25-25 =425-25
2s = 400
Divide by 2
2s/2 =400/2
s =200
Sajini = 200
Now we need to find d
d = s+25
d = 200 + 25
d = 225
Drea = 225