Oxidation states number (OSN) show how many electrons gained, lost or shared during chemical reactions.
Here are some rules of oxidation state numbers.
1. OSN of 1A elements in compounds is +1
2. OSN of Oxygen in compounds is -2
3. Sum of OSN of elements equals zero in neutral compounds.
4. OSN of free elements is zero. ex. F2, N2, O2.. all have 0 OSN.
If an element loses electrons during reaction, it is oxidized. That element is called as reducing agent.
If an element gains electrons during reaction, it is reduced. That element is called as oxidizing agent.
In the given reaction, potassium perchlorate decompose into potassium chlorate and oxygen.
a) KClO4.
K (potassium) is 1A element, OSN +1,
Oxygen in the compound has OSN -2.
Let OSN of Cl be x
1+ x+(4*-2)=0 (since compound is neutral)
Solve the equation. X is equal to +7.
b)Potassium perchlorate is the reactant, Potassium chloride and Oxygen are the products.
Reactants -----> Products
c) Check out change of OSN of elements.
in KCl, OSN number of K is +1, Cl is -1. So Cl+7---->Cl-1. It takes 8 electrons. It was reduced.
in KClO4, OSN number of O is -2, in O2 it becomes O. So O-2---->O. It gives electrons. It was oxidized.
Shortly,
LOSS OF ELECTRONS=OXIDIZED
GAIN OF ELECTRONS=REDUCED
0.052301= 6 sig. figure
400 cm. = 3 significant figures
50.0. =. 3. Significant figure
4500.01=. 6 significant figure
Answer:
Equal
Explanation:
Energy is always conserved in the nature and it is an universal law. According to the law conservation of energy, it is said that energy can never be created out of something and we can never destroy and vanish any energy in any form. Energy in any form can only be transformed to some other forms of energy. This is known as conversion of energy.
In the context, the chemical energy that is produced by the battery and the electrical energy produced should be equal.
Answer:
No change to the cation Add -ide to the anion
Question 1 and .2
Explanation:
When the concentration is expressed in mass percentage, that means there is 3 g of solvent H₂O₂ in 100 grams of the solution. Then, that means the remaining amount of solute is 97 g. We use the value of molarity (moles/liters) to determine the amount of solution in liters, denoted as V. The solution is as follows:
0.02 mol KMnO4/L solution * 158.034 g KMnO4/mol * V = 97 g KMnO4
Solving for V,
V = 30.69 L
