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OLga [1]
3 years ago
11

You have a 5-liter container with 2.00 x 1023 molecules of ammonia gas (NH3) at STP

Chemistry
1 answer:
Svetlanka [38]3 years ago
5 0

Answer:

1.34×10²³ molecules

Explanation:

Given data:

Volume of container = 5 L

Number of molecules of ammonia = 2.00×10²³

Number of molecules of Ar = ?

Volume of container = 5 L

Temperature = 273 K

Pressure = 1 atm

Solution:

PV = nRT

n = PV/RT

n = 1 atm. 5 L / 0.0821 atm. L. mol⁻¹. K⁻¹ . 273.15 K

n = 5 L.atm /22.426 atm. L. mol⁻¹.

n = 0.223 mol

Number of molecules of argon:

One mole = 6.02 ×10²³ molecules

0.223 mol

6.02 ×10²³×0.223

1.34×10²³ molecules

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5.00 of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 128
vitfil [10]

Answer:C10H10

Explanation:

Use a balanced equation to determined quantity of carbon and hydrogen. Then use simple division to determine the empirical formula before the molecula formula

6 0
3 years ago
A gas that occupies 50.0 liters has its volume increased to 68 liters when the pressure was changed to 3.0 ATM. What was the ori
Yuliya22 [10]

Answer:

4.1 atm = 3,116 mmHg = 415.4 kPa

Explanation:

According to Boyle's law, as volume is increased the pressure of the gas is decreased. That can be expressed as:

P₁ x V₁= P₂ x V₂

Where P₁ and V₁ are the initial pressure and volume respectively, and P₂ and V₂ are final pressure and volume, respectively.

From the problem, we have:

V₁= 50.0 L

V₂= 68.0 L

P₂= 3.0 atm

Thus, we calculate the initial pressure as follows:

P₁= (P₂ x V₂)/V₁= (3.0 atm x 68.0 L)/(50.0 L)= 4.08 atm ≅ 4.1 atm

To transform to mmHg, we know that 1 atm= 760 mmHg:

4.1 atm x 760 mmHg/1 atm = 3,116 mmHg

To transform to kPa we use: 1 atm= 101.325 kPa

4.1 atm x 101.325 kPa = 415.4 kPa

5 0
3 years ago
Considering 0.10 m solutions of each substance, which contains the smallest concentration of ions
mihalych1998 [28]

Question options:

A) K2SO4

B) FeCl₃

C) NaOH

D) NH₃

E) KCl

Answer:

D. NH₃

Explanation:

K2SO4 = 2 K+ + SO42-

[K+]= 2 x 1.0 = 2.0 M ; [SO42-] = 1.0 M

total concentrations of ions = 2.0 + 1.0 = <em>3.0 M</em>

FeCl3 = Fe3+ + 3Cl-

[Fe3+] = 1.0 M ; [Cl-] = 3 x 1.0 = 3.0

total concentration ions = 1.0 + 3.0 =<em> 4.0 M</em>

NaOH = Na+ + OH-

[Na+] = [OH-] = 1.0 M

total concentration ions = 1.0 + 1.0 = <em>2.0 M</em>

<u>NH3 is a weak acid so the concentration of NH4+ and OH- </u><u><em>< 2.0</em></u>

KCl = K+ + Cl-

[K+] = [Cl-] = 1.0 M

total concentration ions = 1.0 + 1.0 =<em> 2.0 M</em>

7 0
3 years ago
What will be the end product for each electrode after electrolysis if the solution is concentrated aqueous sodium chloride ?​
Eddi Din [679]

Answer:

Cathode: Hydrogen gas

Anode: Chlorine gas

Explanation:

① Write down the ions present in the electrolyte

Cations: Na⁺, H⁺

Anions: Cl⁻ , OH⁻

② Decide which ions are preferentially discharged.

These are the factors:

For the discharge of cations,

- Reactivity series

(The lower the position of the cation in the reactivity series, the easier it is to be discharged)

For the discharge of anions,

- Concentration effect (look at this first)

(The more concentrated the ion, the easier for it to be discharged)

- If solution is not concentrated (dilute), look at the position of the anion on the electrochemical series.

(The lower the position of the anion on the electrochemical series, the easier of it to be discharged)

In this case:

For cations, H⁺ ions are selectively discharged at the cathode as its position is lower than Na⁺ in the reactivity series.

Anion: Cl⁻ ions, being more concentrated, are selectively discharged at the anode.

☆For electrolysis,

Cation at the cathode (-ve terminal)

Anion at the anode (+ve terminal)

In summary, here's what happened at each electrode:

<u>C</u><u>athode</u>

- H⁺ selectively discharged

- ionic half equation: 2H⁺ (aq) +2e⁻ → H₂ (g)

<u>Anode</u>

- Cl⁻ ions selectively discharged

- ionic half equation: 2Cl⁻ (aq) → Cl₂ (g) + 2e⁻

3 0
3 years ago
What is the molarity of a sodium hydroxide solution containing 2 moles of NaOH with a volume of .5L?
Maksim231197 [3]

Answer:

0.4M NaOH

Explanation:

Molarity, M, is an unit of concentration widely used defined as the ratio between moles of solute (In this case, NaOH) and volume of solution in liters.

As the solution contains 2 moles of NaOH-Moles of solute- in 5L of solution, the molarity is:

2 moles NaOH /  5L =

<h3>0.4M NaOH</h3>
5 0
3 years ago
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