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3 years ago

A mixture of alcohol and water is homogeneous while that of oil and water is heterogeneous.explain

1 answer:

4 0

The solution is said the be homogenous, if it contains single phase. On other hand, heterogenous system contains, multiple phase.

In present case, when <span>alcohol and water are mixed with each other, it forms a single phase. Also, concentration is uniform through out. Hence, it is referred as homogeneous solution.

On other hand, </span>when oil and water are mixed with each other, it forms a two phase. Hence, it is referred as heterogeneous solution.

Polar nature of alcohol favors formation of homogeneous solution with water.

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What is the pH of an aqueous solution with a hydrogen ion concentration of [H ] = 8.2 × 10–4 M?

stira [4]

PH = - log [ H+ ]

pH = - log [ 8.2 x 10⁻⁴]

pH = 3.08

hope this helps!

7 0

3 years ago

How many hydrogen atoms are in 5.10 mol of ammonium sulfide?

Drupady [299]

Answer:

2.46 × 10²⁵ atoms H

Explanation:

Avagadro's Number: 6.022 × 10²³

Step 1: Find formulas

Hydrogen - H

Ammonium Sulfide - (NH₄)₂S

Step 2: Use Dimensional Analysis

$5.10 \hspace{3} mol \hspace{3} (NH_4)_2S(\frac{8 \hspace{3} mol \hspace{3} H}{1 \hspace{3} mol \hspace{3} (NH_4)_2S})(\frac{6.02(10)^{23} \hspace{3} atoms \hspace{3} H}{1 \hspace{3} mol \hspace{3} H} )$ =

Step 3: Simplify

We have 3 sig figs.

2.45616 × 10²⁵ atoms H ≈ 2.46 × 10²⁵ atoms H

4 0

3 years ago

In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for

inessss [21]

Answer:

The standard cell potential of the reaction is 0.78 Volts.

Explanation:

$Cu^{2+}(aq)+Fe(s)\rightarrow Cu(s)+Fe^{2+}(aq)$

Reduction at cathode :

$Cu^+(aq)+2e^-\rightarrow Cu(s)$

Reduction potential of $Cu^{2+}$ to Cu= $E^o_{1}=0.34 V$

Oxidation at anode:

$Fe(s)\rightarrow Fe^{2+}(aq)+2e^-$

Reduction potential of $Fe^{2+}$ to Fe= $E^o_{2}=-0.44 V$

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}$

Putting values in above equation, we get:

$E^o_{cell}=0.34V -(-0.44 V)=0.78 V$

The standard cell potential of the reaction is 0.78 Volts.

3 0

3 years ago

PLEASE HELP MEEEEEEE

Sliva [168]

Amount of copper= mass / molar mass = 17/64=0.2656
According to the balance equation, amount of hydrogen gas : amount of copper = 1:1
Therefore amount of hydrogen gas is 1:1
Thus mass of hydrogen gas is molar mass x mol= 1 x 0.2656= 0.266g

3 0

3 years ago

En el aire, el oxígeno representa el 21%en volumen.

saw5 [17]

Pregunta en guglu ay te ayudara

8 0

3 years ago