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cestrela7 [59]
3 years ago
7

If BC = 6.5, CD = 7.8, and AD = 12.2, find AB to the nearest tenth.

Mathematics
1 answer:
Sladkaya [172]3 years ago
6 0
This can be solved using the angle bisector theorem. Note that line segment AD is the angle bisector of triangle DAB from angle DAB. Therefore, we know that the ratios \frac{\text{AD}}{\text{CD}} and \frac{\text{AB}}{\text{CB}} are equal. Solving, we get \frac{\text{12.2}}{\text{7.8}}=\frac{\text{AB}}{\text{6.5}}. Cross multiplying, we get 79.3 = 7.8x, and solving this equation we get x = 10.1666... \approx 10.2. 10.2 is your answer.
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Step-by-step explanation:

Step 1; Multiply 5 with this matrix  \left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right] and we get a matrix \left[\begin{array}{ccc}-5&10\\20&40\\\end{array}\right]

Multiply the fraction  \frac{2}{5} with the matrix  \left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right] and we get \left[\begin{array}{ccc}-\frac{2m}{5} &\frac{4m}{5} \\\frac{8m}{5} &\frac{16m}{5} \\\end{array}\right]

Step2; Now equate corresponding values of the matrices with each other.

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Step 3; Add the matrices to get the value of matrix m.

Adding the three matrices on the RHS we get  \left[\begin{array}{ccc}2&9&-9\\\end{array}\right].

Step 4; Adding the matrices on the LHS we get the resulting matrix as H +

\left[\begin{array}{ccc}4&6&-8\\\9\end{array}\right]. Equating the matrices from step 3 and 4 we get the value of H as \left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right]

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Step 6; Multiplying we get the matrix m x H = [ -25  \frac{75}{2}  \frac{-25}{2} ]

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