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Flura [38]
3 years ago
14

An attorney charges $250 for an initial meeting and $150 an hour. How many hours can Pablo afford if he has $500? Which equation

would give me the correct answer?
Mathematics
1 answer:
zhuklara [117]3 years ago
8 0

Answer:

1 Hour

250 + 150h = 500

Step-by-step explanation:

So, the fee for the meeting is 250. The hourly fee is 150. Let h equal the number of hours.

250 + 150h

If pablo has 500, then we cannot exceed that amount. So, our equation becomes

250 + 150h = 500

Subtract 250 from both sides

150h = 250

And divide by 50 on both sides. You get x = about 1.67. Since this is a question about time and money, you would round down to 1.

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Rewrite the statement in mathematical notation. (Let y be the distance from the top of the ladder to the floor, x be the distanc
In-s [12.5K]

Answer:

\frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}

Step-by-step explanation:

Let L be the length of the ladder,

Given,

x = the distance from the base of the ladder to the wall, and t be time.

y = distance from the base of the ladder to the wall,

So, by the Pythagoras theorem,

L^2 = y^2 + x^2

\implies L = \sqrt{y^2 + x^2},

Differentiating with respect to time (t),

\frac{dL}{dt}=\frac{d}{dt}(\sqrt{x^2 + y^2})

=\frac{1}{2\sqrt{x^2 + y^2}}\frac{d}{dt}(x^2 + y^2)

=\frac{1}{2\sqrt{x^2 + y^2}}(2x\frac{dx}{dt}+2y\frac{dy}{dt})

=\frac{1}{\sqrt{x^2 +y^2}}(x\frac{dx}{dt}+y\frac{dy}{dt})

Here,

\frac{dy}{dt}=-6\text{ ft per sec}

Also, \frac{dL}{dt} = 0           ( Ladder length = constant ),

\implies \frac{1}{\sqrt{x^2 +y^2}}(x(-6)+y\frac{dy}{dt})=0

-6x + y\frac{dy}{dt}=0

y\frac{dy}{dt}=6x

\implies \frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}

Which is the required notation.

8 0
3 years ago
Can someone help me please?
Rainbow [258]

Answer:

the first option is correct

since value of a will be found through division.

7 0
2 years ago
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Dafna1 [17]

Answer:

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Step-by-step explanation:

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-a²-3b³+c²+2b³-c²

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= 9 - 24 + 9 + 16 - 9

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Answer:

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