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ella [17]
3 years ago
5

A small child is at a candy store, eager to spend his $1 allowance on candy. His two favorite candies are priced at $0.05 and $0

.10, respectively. If the child is intent on spending his entire allowance on candy, which of the following represents a standard form equation that describes this situation?
A. 0.05x+0.10y=1.00

B. 0.10x-0.05y=1.00

C. 5x+10y=100.00

D. x+2y=20.00
Mathematics
2 answers:
andre [41]3 years ago
7 0
It is A. 0.05 represents one of his candies, and x represents how many of those, 0.10 represents the other candy while y represents how many of those candies. 1.00 is the total it should come to.
olga55 [171]3 years ago
4 0

Answer:

a

Step-by-step explanation:

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Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
4 years ago
A help would be greatly appreciated! 
dalvyx [7]
The tree was approximately 40.8ft tall.

You use the equation, a^2+b^2=c^2.
12^2 + 39^2 = x^2, add the results of 12^2 and 39^2 to make 1665 = x^2. You can take the positive root of both sides, 3√185, and it equals 40.80441152, which is rounded to 40.8.
7 0
4 years ago
If sinx=2cosx then, what is the value of sin2x?
Travka [436]
          sin(x) = 2cos(x)
         tan(x) = 2
tan⁻¹[tan(x)] = tan⁻¹(2)
                x ≈ 63.4

sin(2x) = sin[2(63.4)]
sin(2x) = sin(126.8)
sin(2x) ≈ 0.801
3 0
3 years ago
Read 2 more answers
HElP!
zheka24 [161]

Answer:

A- The cabinets have the same base area.

C- The cabinets may have the same base dimensions.

D- The cabinets may have different base dimensions

Step-by-step explanation:

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4 years ago
PLEASE HELP FAST! Giving brainlist, and a bunch of points
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The answer to the question

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