How do I solve this?

1. A jeepney driver claims that his average monthly income is Php 3000.00 with a standard deviation of Php 300.00. A sample of 3

nydimaria [60]

Answer:

Kindly check explanation

Step-by-step explanation:

The hypothesis :

H0 : μ = 3000

H0 : μ ≠ 3000

The test statistic :

(xbar - μ) ÷ (s/√(n))

xbar = 3500

μ = 3000

σ = 300

n = 30

(3500 - 3000) ÷ (350/√(30))

Test statistic = 7.824

Df = 30 - 1 = 29

Tcritical at 0.01 = 2.462

Test statistic > critical value ; we reject H0 ; and concluded that there is significant evidence that

μ ≠ 3000

7 0

4 years ago

Which expression is equivalent to x^-5/3

goblinko [34]

Answer:

c

Step-by-step explanation:

with a fractional exponent, the denominator becomes the root number. so we need a root of 3, which only b and c have.

between those two, b has no negative present whereas c does. since the original exponent was -5/3 we know our answer should have one.

thus c is our answer.

3 0

3 years ago

Which equation is not a linear function? Select each correct function.

tino4ka555 [31]

$\text{The point-slope form of a linear function:}$

$y = mx + b$

$y=xy+2\qquad\text{subtract xy from both sides}\\\\y-xy=2\qquad\text{distributive}\\\\(1-x)y=2\qquad\text{divide both sides by (1 - x)}\\\\y=\dfrac{2}{1-x}\to\text{nonlinear}\\---------------------------\\y=x+2y\qquad\text{subtract 2y from both sides}\\\\-y=x\qquad\text{change the signs}\\\\y=-x\to\text{linear}\\-----------------------------\\y=-x-2y\qquad\text{add 2y to both sides}\\\\3y=-x\qquad\text{divide both sides by 3}\\\\y=-\dfrac{1}{3}x\to\text{linear}\\-----------------------------$

$y=x-y+2\qquad\text{add y to both sides}\\\\2y=x+2\qquad\text{divide both sides by 2}\\\\y=\dfrac{1}{2}x+1\to\text{linear}\\----------------------------\\y=x^2-2+2y\qquad\text{subtract 2y from both sides}\\\\-y=x^2-2\qquad\text{change the signs}\\\\y=-x^2+2\to\text{nonlinear}\\----------------------------\\y=-y+2-2x\qquad\text{add y to both sides}\\\\2y=2-2x\qquad\text{divide both sides by 2}\\\\y=-x+1\to\text{linear}$