Question

Hg2I2(s) ⇄ Hg2 2+(aq) + 2 I−(aq) Ksp = [Hg2 2+][I−]^2 A saturated solution of Hg2I2 is at equilibrium at 25°C as represented by the equation above. If [I−] = 4.6 × 10^−10 M at equilibrium, which of the following gives the correct molar solubility, S, and Ksp for Hg2I2 ?

Answer 1

Answer:

Explanation:

Hg₂I₂ ⇆ Hg₂⁺² + 2I⁻¹

2[I⁻¹ ] = 4.6 x 10⁻¹⁰

[I⁻¹ ] = 2.3 x 10⁻¹⁰ M

[Hg₂⁺²] = 2.3 x 10⁻¹⁰ M

Molar solubility = 2.3 x 10⁻¹⁰ moles / liter

Ksp =  [Hg₂⁺²] x [2I⁻¹ ]²

= 4 x 2.3 x 10⁻¹⁰ x (2.3 x 10⁻¹⁰)²

= 48.67 x 10⁻³⁰ .