Safety.
1 answer:
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Answer:
pH = 10.9
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to say that the undergoing reaction between this buffer and OH⁻ promotes the formation of more CO₃²⁻ because it acts as the base, we can do the following:
The resulting concentrations are:
Thus, since the pKa of this buffer system is 10.2, the change in the pH would be:
Which makes sense since basic OH⁻ ions were added.
Regards!
Explanation:
The given reaction is as follows.
Initial : 0.160 0.160 0
Change : -x -x 2x
Equilibrium: 0.160 - x 0.160 - x x
It is given that = [0.160 - x] = 0.036 M
and, = [0.160 - x] = 0.036 M
so, x = (0.160 - 0.036) M
= 0.124 M
As, [HI] = 2x.
So, [HI] =
= 0.248 M
As it is known that expression for equilibrium constant is as follows.
=
= 47.46
Thus, we can conclude that the equilibrium constant, Kc, for the given reaction is 47.46.