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agasfer [191]
3 years ago
13

Which of the following are examples of matter?a. heat b. sunlight c. water d. grass e. air

Chemistry
1 answer:
OverLord2011 [107]3 years ago
7 0
Sunlight? air? i’m not sure they could all be matter..
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Can someone help me pls
Inessa [10]

Answer:

The heat would flow from the hot solid to the cool solid until all temperatures are near equal.

4 0
3 years ago
Burning a compound of calcium, carbon, and nitrogen in oxygen in a combustion train generates calcium oxide , carbon dioxide , n
mylen [45]

The question is incomplete, here is the complete question:

Burning a compound of calcium, carbon, and nitrogen in oxygen in a combustion train generates calcium oxide (CaO), carbon dioxide (CO_2), nitrogen dioxide (NO_2), and no other substances. A small sample gives 2.389 g CaO, 1.876 g CO_2, and 3.921 g NO_2 Determine the empirical formula of the compound.

<u>Answer:</u> The empirical formula for the given compound is CaCN_2

<u>Explanation:</u>

The chemical equation for the combustion of compound having calcium, carbon and nitrogen follows:

Ca_xC_yN_z+O_2\rightarrow CaO+CO_2+NO_2

where, 'x', 'y' and 'z' are the subscripts of calcium, carbon and nitrogen respectively.

We are given:

Mass of CaO = 2.389 g

Mass of CO_2=1.876g

Mass of NO_2=3.921g

We know that:

Molar mass of calcium oxide = 56 g/mol

Molar mass of carbon dioxide = 44 g/mol

Molar mass of nitrogen dioxide = 46 g/mol

<u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 1.876 g of carbon dioxide, \frac{12}{44}\times 1.876=0.5116g of carbon will be contained.

<u>For calculating the mass of nitrogen:</u>

In 46 g of nitrogen dioxide, 14 g of nitrogen is contained.

So, in 3.921 g of nitrogen dioxide, \frac{14}{46}\times 3.921=1.193g of nitrogen will be contained.

<u>For calculating the mass of calcium:</u>

In 56 g of calcium oxide, 40 g of calcium is contained.

So, in 2.389 g of calcium oxide, \frac{40}{56}\times 2.389=1.706g of calcium will be contained.

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Calcium =\frac{\text{Given mass of Calcium}}{\text{Molar mass of Calcium}}=\frac{1.706g}{40g/mole}=0.0426moles

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.5116g}{12g/mole}=0.0426moles

Moles of Nitrogen = \frac{\text{Given mass of Nitrogen}}{\text{Molar mass of Nitrogen}}=\frac{1.193g}{14g/mole}=0.0852moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0426 moles.

For Calcium = \frac{0.0426}{0.0426}=1

For Carbon = \frac{0.0426}{0.0426}=1

For Nitrogen = \frac{0.0852}{0.0426}=2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of Ca : C : N = 1 : 1 : 2

Hence, the empirical formula for the given compound is CaCN_2

3 0
3 years ago
Where would you find the asthenosphere?
Harman [31]

Answer:

b. upper mantle

Explanation:

low velocity zone of the upper mantle

3 0
3 years ago
Read 2 more answers
Wild animals are not considered a natural resource.
Anvisha [2.4K]

Answer:

False

Explanation:

Wild animals are found in an ecosystem and they are considered to be a natural resource and a biotic factor in the environment. They are living things so they are a natural resource.

4 0
3 years ago
Determine the boiling point of a 3.70 m solution of phenol in benzene. Benzene has a boiling point of 80.1°C and a boiling point
xeze [42]

Answer: The boiling point of a 3.70 m solution of phenol in benzene is 89.5^0C

Explanation:

Elevation in boiling point:

\Delta T_b=i\times k_b\times m

where,

\Delta T_b = change in boiling point

i= vant hoff factor = 1 (for benzene which is a non electrolyte )

k_b = boiling point constant = 2.53^0C/kgmol

m = molality = 3.70

T_{solution}-T_{solvent}=i\times k_b\times m

T_{solution}-80.1^0C=1\times 2.53\times 3.70

T_{solution}=89.5^0C

Thus  the boiling point of a 3.70 m solution of phenol in benzene is 89.5^0C

8 0
3 years ago
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