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Kazeer [188]
2 years ago
10

An airplane 30,000 feet above the ground begins descending at a rate of 2,000 feet per minute. Write an equation to model the si

tuation. Find the altitude of the plane after 5 minutes
Mathematics
1 answer:
antiseptic1488 [7]2 years ago
6 0
A = 30,000 - 2000m where A=altitude and m = number of minutes

After 5 minutes A ( altitude) = 30,000 - 2000(5) = 20,000 feet
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Tpy6a [65]

replace the numbers inside () for x

 f(4) = -4(4)-3 = -16 -3 = -19

G(-4) = 2(-4)^2 -3(-4) = 44

7 0
3 years ago
A traditional postage stamp has a width of 4/5 inches and a length of 9/10. What is the area of a traditional postage stamp?
Illusion [34]
4/5*9/10= 36/50 = 18/25

Just multiply the fractions straight across since area is length*height
5 0
3 years ago
Read 2 more answers
Please I need help in this question, Best answer gets BRAINLIEST
Nata [24]

Answer:

1 - a/variable

2 - d/statistic

3 - b/population

4 - c/data

5 - e/parameter

6 - f/sample

I did comment asking if the two you'd already selected were definitely correct, but no answer was given, so I apologise if this is wrong. This is what I would put.

7 0
3 years ago
The area of one of the smaller circles is 8/ in². Find the area of the shaded region.
Ksju [112]

Answer:

Area of shaded region = 16π in² (D)

Step-by-step explanation:

The question is incomplete without the diagram if the circles. Find attached the diagram used in solving the question.

Area of the smaller circle = 8π in²

Area of a circle = πr²

πr² = 8π

r² =8

r = √8 = 2√2

From the diagram, there are two smaller circles in a bigger circle.

The radius of the bigger circle (R) is 2times the radius of the smaller circle (r)

R = 2r

Area of bigger circle = πR²

= π×(2r)² =   π×(2×2√2)²

= π×(4√2)² = π×16×(√2)²

Area of bigger circle = π×16×2

Area of bigger circle = 32π in²

Since there are two smaller circles in a bigger circle

Area of shaded region = Area of bigger circle -2(area of smaller circles)

Area of shaded region = 32π in² - 2(8π in²)

Area of shaded region = 32π in² - 16π in²

Area of shaded region = 16π in²

8 0
3 years ago
6. Evaluate 7C4.<br> 840<br> 210<br> 6<br> 35
AleksAgata [21]

Answer:

210

Step-by-step explanation:

8 0
3 years ago
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