Probaility is (desired outcomes)/(total possible outcomes)
odd numbers of dice is 3 (1,3,5)
desired outcomes =3
dice has 6 numbers
total possible outcomes of diece=6
3/6=1/2=dice
coin
tails=1
desired outcomes=1
total possibe=2 since 2 sides (head and tails)
cond poinbabiotiuyy=1/2
they are independend of each other since they do not influence each other
if they were like 'pick 2 collor balls and see what color you get, when you pick one, there is 1 less ball int he bucket so the propbabilit changes'
so
assuming that
P(M and N)= means
'the probability of M and N are both equal to "
The two events are independent. In the given scenario, P(M and N) =1/2.
Answer:
7.2
Step-by-step explanation:
Given that in triangle LMN, LO is angle bisector of angle L.
LN =10 and LM =18
By angle bisector theorem for triangles we have
LN/LM = NO/MO
Substitute the values for known things and x for MO
We get
10/18 = 4/x
Or cross multiply to get
10x=72
x=7.2
So answer is 7.2
Hello,
aPb=b*(b-1)*(b-2)*....*(b-a+1) / a!
3P5=5*4*3/(3*2*1)=10
If we name the number of the employers 1,2,3,4,5
Here are the choices:
123,124,125,134,135,145,234,235,245,345 (total 10 choices)
Check the picture below.
let's recall that a kite is a quadrilateral, and thus is a polygon with 4 sides
sum of all interior angles in a polygon
180(n - 2) n = number of sides
so for a quadrilateral that'd be 180( 4 - 2 ) = 360, thus
![\bf 3b+70+50+3b=360\implies 6b+120=360\implies 6b=240 \\\\\\ b=\cfrac{240}{6}\implies b=40 \\\\[-0.35em] ~\dotfill\\\\ \overline{XY}=\overline{YZ}\implies 3a-5=a+11\implies 2a-5=11 \\\\\\ 2a=16\implies a=\cfrac{16}{2}\implies a=8](https://tex.z-dn.net/?f=%5Cbf%203b%2B70%2B50%2B3b%3D360%5Cimplies%206b%2B120%3D360%5Cimplies%206b%3D240%20%5C%5C%5C%5C%5C%5C%20b%3D%5Ccfrac%7B240%7D%7B6%7D%5Cimplies%20b%3D40%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Coverline%7BXY%7D%3D%5Coverline%7BYZ%7D%5Cimplies%203a-5%3Da%2B11%5Cimplies%202a-5%3D11%20%5C%5C%5C%5C%5C%5C%202a%3D16%5Cimplies%20a%3D%5Ccfrac%7B16%7D%7B2%7D%5Cimplies%20a%3D8)
Answer: Depends on the elephant ;)
