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3 years ago

Thanks an advance~! Show your work :)

Mathematics

1 answer:

Talja [164]3 years ago

6 0

Only AAS cannot prove this.

So the answer will be A.

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True or false: Least squares regression problems always have a unique solution, since they are modelled by the normal equation

Vilka [71]

Answer: (((trueeee))))

4 0

2 years ago

4) Graph f(x) 2(3)*. Compare the graph to the

Naddik [55]

Answer it is 65

Step-by-step explanation:

6 0

3 years ago

What makes this bond correct <br> 3/4+__=2<br> WHATS THE ANSWER

VladimirAG [237]

Answer:

The answer is 5/6.

Step-by-step explanation:

Lets start with a=1.

a+1=2, which is the denominator. (1/2)

Taking the same number as numerator, now, consider a=2.

a+1=3, denominator.(2/3)

Now, let a=3.

a+1==4, denominator for a=3. (3/4)

If continued a becomes equal to 4.

a+1=5, which is also the denominator. (4/5)

Now, since the denominator is 5, let a=5.

a+1=6, which will become the denominator. (5/6)

Thus the series follows a pattern of a/a+1.

4 0

2 years ago

Read 2 more answers

Need help with this please

OLga [1]

Answer:

k= -2

Step-by-step explanation:

you are dividing the x by -2 each time

3 0

3 years ago

What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c

zysi [14]

Answer:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

Step-by-step explanation:

Given

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Required

Simplify

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Cancel out 18

$\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}$

Divide 4 and 2

$\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}$

Divide 27 and 12 by 3

$\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}$

Apply law of indices

$\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}$

$\frac{9a^5 * b^3 * 2c }{4}$

Divide 2 and 4

$\frac{9a^5 * b^3 * c}{2}$

$\frac{9a^5b^3c}{2}$

Rewrite as:

$\frac{9}{2}a^5b^3c$

Hence:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

4 0

2 years ago