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Debora [2.8K]
3 years ago
12

Check all of the infinite geometric series that diverge.

Mathematics
1 answer:
Airida [17]3 years ago
3 0

Answer: b and d

Step-by-step explanation:

On edge

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Name the postulate or theorem you can use to prove NPM=OMP
Katarina [22]

Answer:

ΔNPM and ΔOMP by SAS postulate

B is correct

Step-by-step explanation:

In ΔNPM and ΔOMP

    NP = OM              (Given)

∠NPM = ∠OMP         (Given)

     PM = MP              ( Common )

So, ΔNPM ≅ ΔOMP by SAS property of concurrency.

ΔNPM and ΔOMP are congruent because their two side and angle between them are equal.

Therefore, SAS postulate use here

Hence, ΔNPM and ΔOMP by SAS postulate

4 0
3 years ago
Find an ordered pair x,y 4x-y=5
allochka39001 [22]

y=2X-5 and 4X-Y=7

Putting the value of Y in 2nd equation:

4x-2x+5=7

2x=7-5

2x=2

OR,x=2/2=1

 

putting the value of x in equation 1:

y=2x-5

y=2*1-5

y=2-5

y=-3

 

6 0
3 years ago
A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when
Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

ME = Zc * σ \sqrt{n}

ME = 1.96 * 3 \sqrt{25}

ME = 1.18

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})

CI = (57.12 , 59.48)

b)

Given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

ME = zc * σ \sqrt{n}

ME = 1.96 * 3\sqrt{100}

ME = 0.59

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})

CI = (57.71 , 58.89)

c)

sample mean, \bar X = 58.3

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

ME = Zc * σ \sqrt{n}

ME = 2.58 * 3\sqrt{100}

ME = 0.77

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

n \geq (zc *σ/E)^2

n = (2.58 * 3/0.5)^2

n = 239.63

7 0
3 years ago
Help in these two! See these questions below.
GrogVix [38]

Answer:

16. y = 7x

17. y = x + 6

4 0
3 years ago
A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t) = 52t - 16t^2 . What i
ahrayia [7]

Answer:

42.25 feet

Step-by-step explanation:

The height function is a parabola.  The maximum value of a negative parabola is at the vertex, which can be found with:

x = -b/2a

where a and b are the coefficients in y = ax² + bx + c.

Here, we have y = -16t² + 52t.  So a = -16 and b = 52.  The vertex is at:

t = -52 / (2×-16)

t = 13/8

Evaluating the function:

h(13/8) = -16(13/8)² + 52(13/8)

h(13/8) = -169/4 + 169/2

h(13/8) = 169/4

h(13/8) = 42.25

7 0
3 years ago
Read 2 more answers
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