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After the addition of the last two teaspoons of salt, the solution is saturated
A solution is saturated when it has the highest amount of solute (in this case the salt) that the solvent (in this case the water) can dissolve at that pressure and temperature.
Visually, a saturated solution can be detected when the adding of more solute results in the settling of solute grains (in this case salt) at the bottom of the container, because the solvent couldn't dissolve them at that pressure and temperature. That's why we can say that the solution is saturated.
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Al will have a higher first and third ionization energy
We can use the ideal gas law equation to find the volume occupied by oxygen gas
PV = nRT
where ;
P - pressure - 52.7 kPa
V - volume
n - number of oxygen moles - 12.0 g / 32 g/mol = 0.375 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 25 °C + 273 = 298 K
substituting the values in the equation
52 700 Pa x V = 0.375 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
V = 17.6 L
volume of the gas is 17.6 L
Answer:
7.00
Explanation:
When the solutions are mixed, the HCl dissociates to form the ions H+ and Cl-. The ion H+ will react with the NH3 to form NH4+. The stoichiometry for this is 1 mol of HCl to 1 mol of H+ to 1 mol of Cl-, and 1 mol of H+ to 1 mol of NH3 to 1 mol of NH4+.
First, let's find the number of moles of each one of them, multiplying the concentration by the volume:
nH+ = 0.15 M * 25 mL = 3.75 mmol
nNH3 = 0.52 M * 25 mL = 13 mmol
So, all the H+ is consumed, and the neutralization is completed, thus pH will be the pH of the solvent (water), pH = 7.00.
It is B, and also for a moment I didn't understand that 4.69 x 10^22. I almost did this whole problem wrong.
