All categories

3 years ago

The following neutral atoms each have 8 places for electrons in their outermost shells.

Chemistry

2 answers:

Lunna [17]3 years ago

7 0

C. ne with 8 valenc3 electrons

Sav [38]3 years ago

4 0

Answer:

a. Li with 1 valence electron

Explanation:

For this it is necessary to see the electronegativity of this atoms. The electronegativity is the force or tendency that has an atom to attract electrons, so the atom who has the lower value of electronegativity is the one that will tend to lose rather than gain electrons.

The electronegativity of these atoms is:

Li – 0.98

O – 3.44

F – 3.98

Ne is a noble gas so has no tendency to gain nor lose electrons

You might be interested in

6. How will you obtain ? (a) Magnesium oxide from magnesium. (b) Silver chloride from silver nitrate. (c) Nitrogen dioxide from

Reil [10]

Answer:

a) reaction with oxygen

2mg +o2---------2mgo

b) Agno3+NaCl ----------AgCl+NaNo3

8 0

2 years ago

Which of these elements in group 1A has the largest atomic radius? Cesium, Rubidium, Potassium, or Sodium?

Savatey [412]

Cesium is the element in group 1A that has the largest atomic radius, with the number of 225.
Rubidium has 211, Potassium 196, and Sodium 154.

8 0

4 years ago

Read 2 more answers

Lithium acetate, LiCH3CO2, is a salt formed from the neutralization of the weak acid acetic acid, CH3CO2H, with the strong base

Vesna [10]

Answer : The pH of 0.289 M solution of lithium acetate at $25^oC$ is 9.1

Explanation :

First we have to calculate the value of $K_b$ .

As we know that,

$K_a\times K_b=K_w$

where,

$K_a$ = dissociation constant of an acid = $1.8\times 10^{-5}$

$K_b$ = dissociation constant of a base = ?

$K_w$ = dissociation constant of water = $1\times 10^{-14}$

Now put all the given values in the above expression, we get the dissociation constant of a base.

$1.8\times 10^{-5}\times K_b=1\times 10^{-14}$

$K_b=5.5\times 10^{-10}$

Now we have to calculate the concentration of hydroxide ion.

Formula used :

$[OH^-]=(K_b\times C)^{\frac{1}{2}}$

where,

C is the concentration of solution.

Now put all the given values in this formula, we get:

$[OH^-]=(5.5\times 10^{-10}\times 0.289)^{\frac{1}{2}}$

$[OH^-]=1.3\times 10^{-5}M$

Now we have to calculate the pOH.

$pOH=-\log [OH^-]$

$pOH=-\log (1.3\times 10^{-5})$

$pOH=4.9$

Now we have to calculate the pH.

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-4.9=9.1$

Therefore, the pH of 0.289 M solution of lithium acetate at $25^oC$ is 9.1

4 0

4 years ago

The company's chief financial officer recognizes the need for an upgrade to the smart watches but does not understand why the bu

goldenfox [79]

Answer:

how about you just put whats on your mind and continue on

Explanation:

no need to ask this question just answer it and move on or you will lose your sanity trying to figure this out

7 0

3 years ago

Read 2 more answers

Give the number and type of hybrid orbital that forms when each set of atomic orbitals mixes:

evablogger [386]

<u>Two hybrid </u>orbitals of <u>sp </u>type forms when each set of atomic orbitals mixes one p and one s

<h3>What is orbital hybridization?</h3>

In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.

For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.

Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.

Learn more about Hybridization

brainly.com/question/22765530

#SPJ4

8 0

2 years ago