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3 years ago

The following neutral atoms each have 8 places for electrons in their outermost shells.

Chemistry

2 answers:

Lunna [17]3 years ago

7 0

C. ne with 8 valenc3 electrons

Sav [38]3 years ago

4 0

Answer:

a. Li with 1 valence electron

Explanation:

For this it is necessary to see the electronegativity of this atoms. The electronegativity is the force or tendency that has an atom to attract electrons, so the atom who has the lower value of electronegativity is the one that will tend to lose rather than gain electrons.

The electronegativity of these atoms is:

Li – 0.98

O – 3.44

F – 3.98

Ne is a noble gas so has no tendency to gain nor lose electrons

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PLEASE SOMEONE HELP ME WITH THIIS QUESTION

sdas [7]

Answer:

The correct answer is - 5 carbon compounds due to low to high intermolecular forces between their molecules.

Explanation:

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3 0

3 years ago

How many atoms are in 10.1 g Ne

LekaFEV [45]

Answer:

3.01 × 10²³ atoms Ne

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Tables
Moles

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

Identify

[Given] 10.1 g Ne

[Solve] atoms Ne

Step 2: Identify Conversions

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

[PT] Molar Mass of Ne: 20.18 g/mol\

Step 3: Convert

[DA] Set up: $\displaystyle 10.1 \ g \ Ne(\frac{1 \ mol \ Ne}{20.18 \ g \ Ne})(\frac{6.022 \cdot 10^{23} \ atoms \ Ne}{1 \ mol \ Ne})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 3.01398 \cdot 10^{23} \ atoms \ Ne$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

3.01398 × 10²³ atoms Ne ≈ 3.01 × 10²³ atoms Ne

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3 years ago