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Svetllana [295]
2 years ago
10

Now look at the segment of the graph between the two data points marked with red squares. Describe how the boiling point and mel

ting point plots behave for these points. ​
The melting and boiling points are the practically the same for each element

The melting points are higher than the boiling points for each element

The boiling points are higher than the boiling points for each element
Chemistry
2 answers:
laila [671]2 years ago
6 0
B maybe not to sure I think so though
yKpoI14uk [10]2 years ago
4 0

I cant do much without the image but C might be it. Again i cant know for sure without the image.

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The chemical formula for baking soda is NaHCO. Does baking soda contain metallic or non-metallic elements? Which one is which?
Fed [463]

Answer:

Both metals and non metals.

Explanation:

The correct formula of baking soda is NaHCO₃,

An element is considered to be metal if it is able to give electron easily due to very low ionization energy.

A non metal is ready to accept electron easily due to high electron affinity.

In sodium bicarbonate :

Na: Sodium : metal

H : Hydrogen: non metal (although placed with first group, alkali metals, in the periodic table as it readily loses electron like metals)

C: Carbon: Non metal

O : Oxygen : Non metal.

So the compound contains both metals and non metals.

3 0
3 years ago
1718 l of a 0.3556-m c3h7oh solution is diluted to a concentration of 0.1222 m, what is the volume of the resulting solution
Agata [3.3K]
Answer : The volume of the resulting solution will be 0.4999 L.

Explanation : As the two molar concentration of the C_{3} H_{7}OH solution are given and one of the volume concentration needs to be found.

So, according to the formula :-  m_{1}V_{1} = m_{2}V_{2}

And here if we consider V_{1} as 0.1718 L moles and m_{1}  as 0.3556 moles then we need to find V_{2} as m_{2}  is given as 0.1222 moles.
Hence on solving the formula we get,  

 V_{2} = (0.1718 X 0.3556) / 0.1222 = 0.4999 L

 


5 0
3 years ago
Dr. Thomas was doing laundry and accidentally knocked over the entire bottle of liquid laundry detergent (true story!). What wou
neonofarm [45]
Baking soda is the correct
7 0
3 years ago
What volume of a 0.35M solution of sodium chloride could be formed with 25 grams of NaCl?
Margaret [11]

Answer:

A concentrated solution has a greater amount of dissolved solute than a dilute solution. Explanatio ...  More

6 0
2 years ago
When 47.1 J of heat is added to 14.0 g of a liquid, its temperature rises by 1.80 ∘C. What is the heat capacity of the liquid?
Alja [10]

Answer:

\boxed {\boxed {\sf 1.87 \J/g \textdegree C}}

Explanation:

We are asked to find the specific heat capacity of a liquid. We are given the heat added, the mass, and the change in temperature, so we will use the following formula.

q= mc\Delta T

The heat added (q) is 47.1 Joules. The mass (m) of the liquid is 14.0 grams. The specific heat (c) is unknown. The change in temperature (ΔT) is 1.80 °C.

  • q= 47.1 J
  • m= 14.0 g
  • ΔT= 1.80 °C

Substitute these values into the formula.

47.1 \ J = (14.0 \ g) * c * (1.80 \textdegree C)

Multiply the 2 numbers in parentheses on the right side of the equation.

47.1 \ J = (14.0 \ g * 1.80 \textdegree C)*c

47.1 \ J = (25.2 \ g*\textdegree C) *c

We are solving for the heat capacity of the liquid, so we must isolate the variable c. It is being multiplied by 25.2 grams * degrees Celsius. The inverse operation of multiplication is division, so we divide both sides of the equation by (25.2 g * °C).

\frac {47.1 \ J}{(25.2 g *\textdegree C)} = \frac {(25.2 g *\textdegree C)*c}{{(25.2 g *\textdegree C)}}

\frac {47.1 \ J}{(25.2 g *\textdegree C)} =c

1.869047619 \ J/g *\textdegree C = c

The original measurements of heat, mass, and temperature all have 3 significant figures, so our answer must have the same. For the number we found that is the hundredth place. The 9 in the thousandth place to the right tells us to round the 6 up to a 7.

1.87 \ J/ g * \textdegree C =c

The heat capacity of the liquid is approximately 1.87 J/g°C.

3 0
3 years ago
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