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Svetllana [295]
2 years ago
10

Now look at the segment of the graph between the two data points marked with red squares. Describe how the boiling point and mel

ting point plots behave for these points. ​
The melting and boiling points are the practically the same for each element

The melting points are higher than the boiling points for each element

The boiling points are higher than the boiling points for each element
Chemistry
2 answers:
laila [671]2 years ago
6 0
B maybe not to sure I think so though
yKpoI14uk [10]2 years ago
4 0

I cant do much without the image but C might be it. Again i cant know for sure without the image.

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ILL GIVE BRAINLIST IF YOU GET IT RIGHT Which of the following is an example of gravitational potential energy?
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A glass jar sitting on a shelf.

If the shelf gets tipped the jar will slide off and convert to kinetic energy as gravity pulls it to land on the next level/floor
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2 years ago
State whether the sign of the entropy change expected for each of the following processes will be positive or negative, and expl
Strike441 [17]

Answer:

a) ΔS is negative

b) ΔS is positive

c) ΔS is positive

d) ΔS is negative

Explanation:

Entropy (S) is a thermodynamic parameter which measures the randomness or the disorder in a system. Greater the disorder more positive will be the value of entropy.

The extent of disorder increases as substances transition from the solid to the gaseous state. i.e.

S(solid) < S(liquid) < S(gas)

The entropy change for a given reaction is:

\Delta S = S(products)-S(reactants)----(1)

a) PCl3(l) + Cl2(g) \rightarrow PCl5(s)

Here  the reactants are in the liquid and gas phase which have higher entropy than the product which is in the solid phase i.e. lower entropy.

Since S(product) < S(reactant), based on equation 1, ΔS will be negative.

b) 2HgO(s) \rightarrow 2Hg(l) + O2(g)

Here the products are in the liquid and gas phase which have higher entropy than the reactant which is in the solid phase i.e. lower entropy.

Since S(product) > S(reactant), based on equation 1, ΔS will be positive.

c) H2(g) \rightarrow 2H(g)

Here the products and reactants are in the gas phase. However the number of moles of products is greater than the reactants

Since S(product) > S(reactant), based on equation 1, ΔS will be positive.

d) U(s) + 3F2(g) \rightarrow UF6(s)

Here  one of the reactants is in the gas phase which corresponds to a more positive entropy compared to the  product which is in the solid phase i.e. lower entropy.

Since S(product) < S(reactant), based on equation 1, ΔS will be negative.

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3 years ago
Which family of the periodic table forms ions with a -1 charge
Anon25 [30]

Answer:

ur mom

sorry I had to :(((

5 0
3 years ago
Arrange the following H atom electron transitions in order of increasing frequency of the photon absorbed or emitted:
ololo11 [35]

Hence the order of the transition in order of increasing frequency of the photon absorbed or emitted  will be : d < a < c < b

E = -13.6×Z²/n²

where,

E = energy of  orbit

n = number of orbit

Z = atomic number

Energy of n = 1 in an hydrogen atom:

E₁ = -13.6× 1²/1² = -13.6eV

Energy of n = 2 in an hydrogen atom:

E₂ = -13.6 × 1²/2² = -3.40eV

Energy of n = 3 in an hydrogen atom:

E₃ = -13.6× 1²/3² = -1.51eV

Energy of n = 4 in an hydrogen atom:

E₄ = -13.6× 1²/4² = -0.85eV

Energy of n = 5 in an hydrogen atom:

E₃ = -13.6× 1²/ 5² = -0.54eV

a) n = 2 to n = 4 (absorption)

ΔE₁ = E₄ - E₂ = -0.85- (- 3.40) = 2.55eV

b) n = 2 to n = 1 (emission)

Δ E₂ = E₁ - E₂ = -13.6 - (- 3.40) = -10.2eV

Negative sign indicates that emission will take place.

c) n = 2 to n = 5 (absorption)

ΔE₃ = E₅ - E₂ = -0.54 -( -3.40) = -2.85eV

d) n = 4 to n = 3 (emission)

ΔE₄ = E₃ - E₄ = -1.51 - (- 0.85) = - 0.66eV

Negative sign indicates that emission will take place.

According to Planck's equation, higher the frequency of the wave higher will be the energy:

E = hv

h = Planck's constant

v =frequency of the wave

So, the increasing order of magnitude of the energy difference :

E₄< E₁ <E₃ <E₂

The  H atom electron transitions in order of increasing frequency of the photon absorbed or emitted will be d < a < c < b

: d < a < c < b

To learn more about transitions visit the link:

brainly.com/question/28304182?referrer=searchResults

The question is incomplete , complete question is:

Arrange the following H atom electron transitions in order of increasing frequency of the photon absorbed or emitted:

(a) n = 2 to n = 4

(b) n = 2 to n = 1

(c) n = 2 to n = 5

(d) n = 4 to n = 3

#SPJ4

6 0
2 years ago
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