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Blizzard [7]
3 years ago
8

Lipids that are liquid at room temperature are known as ____.

Chemistry
1 answer:
zaharov [31]3 years ago
7 0
Lipids that are liquid at room temperature are known as oils.
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If Jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy, _____... is being
Pachacha [2.7K]

<u>Answer;</u>

-Work

If Jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy, <u>work </u> is being done.

<u>Explanation;</u>

  • Work refers to the application of a given force over a distance. Thus, we can say work is the product of force and distance.
  • Energy on the other hand is the ability of a body to change, its location, shape, or state of another body.
  • According to the work-Energy principle, a change in the kinetic energy, which is the energy possessed by a body in motion, is equivalent to the net work done on the body.
8 0
3 years ago
Read 2 more answers
The Earth's mantle is
EleoNora [17]

Answer:

C. cooler than both the crust and the core

Explanation:

It is observed that at the mantle, temperatures range from estimatedly 200 °C (392 °F) around the upper boundary with the crust to approximately 4,000 °C (7,230 °F) at the core-mantle boundary.

So we can say the mantle is cooler than both the crust and the core.

5 0
3 years ago
There is a boy i like. i don't think he like me what do i do
SCORPION-xisa [38]

Answer:

tell em

Explanation:

7 0
3 years ago
What has law is in use when you place dry ice into a balloon
inn [45]

Answer:

When dry ice is exposed to warm air, a gas called carbon dioxide is produced through a process called sublimation

Explanation:

4 0
3 years ago
What is the pressure of 0.33 moles of nitrogen gas, if its volume is 15.0 L at –25.0oC?
musickatia [10]

Using the ideal gas law PV =nRTPV=nRT , we find that the pressure will be P =\frac{nRT}{V}P=

V

nRT

​

 . Then, we'll substitute and find the pressure, using T = -25 °C = 248.15 K and R = 0.0821 \frac{atm\cdot L}{mol \cdot K}

mol⋅K

atm⋅L

​

 :

P =\frac{nRT}{V} = \frac{(0.33\,\cancel{mol})(0.0821\frac{atm\cdot \cancel{L}}{\cancel{mol \cdot K}})(248.15\,\cancel{K})}{15.0\,\cancel{L}} = 0.4482\,atmP=

V

nRT

​

=

15.0

L

​

(0.33

mol

)(0.0821

mol⋅K

atm⋅

L

​

​

)(248.15

K

​

)

​

=0.4482atm

In conclusion, the pressure of this gas is P=0.4482 atm.

Reference:

Chang, R. (2010). Chemistry. McGraw-Hill, New York.

3 0
2 years ago
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