Answer B
the first curve stops on (1 ; 3) excluded (x < 1)
and
the straight line starts on (1 ; 1) included (x ≥ 1)
Step-by-step explanation:
solution
or,-8p=40
or, p=40/-8
or, p=-5
For this you need to expand the brackets first:
3(2x+5)-4(2x-7) = 6x+15-8x-28
And then now you need to add and simplify:
6x+15-8x-28 —> 6x-8x= -2x
15-28= -13
So that leaves
-2x - 13
Answer:
Step-by-step explanation:
<u>Part A: the x-intercepts are -3/2 and 5/2 </u>
- 4
- 7x - 15 -----> (2x + 3) (2x - 5)
2x + 3 = 0 --------> 2x = -3 ----------> x = 
2x - 5 = 0 ---------> 2x = 5 -----------> x = 
<u>Part B: the parabola is a minimum, the vertex is (7/8,-289/16) </u>
f(x)=ax^2+bx+c
if a>0, then the parabola opens up and the vertex is a minimum
a<0 then the parabola opens down and the vertex is a max
the x value of the vertex in f(x)=ax^2+bx+c= is -b/(2a)
the y value of the vertex is f(-b/(2a))
f(x) = 4
- 7x - 15
a = 4
b = -7
-b/2a=-(7)/(2*4)=7/8
f(7/8) = 4
- 7(7/8) - 15
f(7/8) = 49/16 - 49/8 - 15
f(7/8) = -289/16
-
the vertex is (7/8,-289/16)
<u>Part C: </u>
- the vertex is minimum and the graph goes through the x intercepts
- plug in x values to get the y value (EX: choose 0 for x, and you'll get -15 for y, so you would plot the point at (0, -15). you could plug in 1 for x, and get -18 for y, plotting the point (1, -18) )