Answer:
12 units
Step-by-step explanation:
Given the points :
R(−3, 2) - - - > S(2, 2) - - - - > T(2, −5).
Distance between R and S
Distance between two points is obtained thus :
D = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Distance between R and S
x1 = - 3 ; y1= 2 ; x2 = 2 ; y2 = 2
D1 = sqrt((2 - (-3))^2 + (2 - 2)^2)
D1 = sqrt((5^2 + 0^2))
D1 = sqrt(25)
D1 = 5
Distance between S and T
x1 = 2 ; y1= 2 ; x2 = 2 ; y2 = - 5
D2 = sqrt((2 - 2)^2 + (-5 - 2)^2)
D2 = sqrt((0^2 + (-7)^2))
D2 = sqrt(49)
D2 = 7
Hence, total length = D1 + D2 = 5 + 7 = 12 units
9
230-18.84=211.16
211.16-116.22=94.94
94.94-42.13=52.81
52.81-93.17=-40.36
-40.36-50=-90.36
-90.36-13.12-50=-153.48
-153.48
Answer:
BD = √13cm, AC = 10c,
Step-by-step explanation:



Answer:
257.5 mph
332.5 mph
Step-by-step explanation:
The initial distance between the two planes is 960 miles, while the final distance (after t=1.5 h) is 75 miles, so the total distance covered by the two planes in 1.5h is
miles
Calling v1 and v2 the velocities of the two planes, we have the following equations:
(1)
--> velocity of plane 1 exceeds velocity of plane 2 by 75 mph
(2)
--> the total distance covered by the two planes is 885 miles (t=1.5 h is the time, and the products v1 t and v2 t represent the distance covered by each plane)
Substituting t=1.5 h, the second equation becomes:

By substituting (1) into this last equation, we find:

And substituting this back into eq.(1), we find

So, the speeds of the two planes are
257.5 mph
332.5 mph
Answer:
Answer in the picture: x = 1 | y = -5
Step-by-step explanation:
Not sure if that's the answer you're looking for but I think that's it