Let's consider an arbitrary 2x2 matrix as an example,

The columns of

are linearly independent if and only if the column vectors

are linearly independent.
This is the case if the only way we can make a linear combination of

reduce to the zero vector is to multiply the vectors by 0; that is,

only by letting

.
A more concrete example: suppose

Here,

and

. Notice that we can get the zero vector by taking

and

:

so the columns of

are not linearly independent, or linearly dependent.
Answer:
For number 2 the answer is 8/6=20/15
The answer for 3 is 12:26
Step-by-step explanation:
Answer:
a. (-1, 3)
Step-by-step explanation:
The "glide" 4 units right and up is the transformation ...
(x, y) ⇒ (x+4, y+4)
The reflection across y=1 is the transformation ...
(x, y) ⇒ (x, 2-y)
Combined, you have the transformation ...
(x, y) ⇒ (x +4, 2-(y +4)) = (x +4, -2-y)
Then, ...
K(-5, -5) ⇒ K'(-5 +4, -2-(-5)) = K'(-1, 3)
Answer:
a. 254.34, b. 56.52
Step-by-step explanation:
a. A = πr^2,
A = 3.14(9^2)
A = 3.14*81
A = 254.34
b. C = πd
C = 18*3.14
C = 56.52
You flip the sign from > to < only when you are dividing by a negative number and in this case it would be negative 9.