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2 years ago

1 3/4 miles in twenty minutes

Mathematics

1 answer:

nikitadnepr [17]2 years ago

8 0

No instructions? I'll assume you want the unit rate.

4 miles in 36 minutes = 4/36 miles in 1 minute, or 1/9 mile in 1 minute.

1 3/4 mile in 20 minutes? Multiply both figures by 3:

7 miles in 60 minutes, or 7 miles in 1 hour, or 7 mph.

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Eric has $100,000 in savings account.The interest rate is 8 % per year and is not compounded.To the nearest Dollar,how much will

Roman55 [17]

Answer:

To calculate the simple interest, we say

S.I = (PxRxT)/100

Where P = the principal amount

R= rate in terms of %

And T= time.

Now P= $100 000

R= 8%

T= 3 years

S.I= (100,000 x8 x3)/100

=$2 400 000/100

= $24, 000

So the interest is 24000

Total amount he will be having = 100000 + 24 000

The total money he will be having in 3 years time = $124 000

Step-by-step explanation:

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2 years ago

last year, Carmen opened an investment account with $7400. At the end of the year, the amount in the account had decrease buy 26

kvasek [131]

The account decreased by
7,400×0.265=1,961

The account at the end of the year
7,400−1,961=5,439

4 0

3 years ago

What is the square root of 150 and 136? Thanks :)

algol13

The square root of 150 is 12.2474487139. The square root of 136 is 11.6619037897. And your welcome :)

7 0

3 years ago

Is x^2-8x+64 a perfect square trinomial

Ann [662]

Answer:

No, it is not.

Step-by-step explanation:

There is no way to simply this trinomial into two identical binomials.

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2 years ago

In Spring 2017, data was collected from a random selection of STA 2023 students. One of the questions asked how many hours they

Arte-miy333 [17]

Answer: 0.22

Step-by-step explanation:

We know that the best point estimate for the difference between two population mean is the difference between their sample means.

Given : For the 39 randomly selected upperclassmen, the sample mean was 0.12 and sample standard deviation was 0.42. For the 35 randomly selected underclassmen, the sample mean was 0.34 and the sample standard deviation was 0.87.

Let A denotes the population of upperclassmen and B denotes the population of underclassmen .

$\overline{x}_A=0.12$

$\overline{x}_B=0.34$

Then, the point estimate of the difference in the population mean volunteered between underclassmen and upperclassmen will be :-

$\overline{x}_B-\overline{x}_A=0.34-0.12=0.22$

Hence, the point estimate of the difference in the population mean volunteered between underclassmen and upperclassmen =0.22

5 0

3 years ago