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Verizon [17]
3 years ago
11

the stilts increase a persons height by 1.5 yards.if bonnie,who is 5 feet and 7 inches tall, walks with the stilts, how tall wil

l she be?
Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
7 0
There's three feet in a yard and if you have one yard that's already 3 feet then add half a yard (half of three) that's 1.5 feet. Add 4 feet to 5 feet then add the six inches to seven inches because 6 inches is half of a foot, and you will end up with
10'1
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Given ΔABC with A(–4, –2), B(4, 4), and C(18, –8), write the equation for the line containing median segment The term is line se
Monica [59]
Here we want to find the equation of the line containing the median CP.

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\displaystyle{ P=( \frac{-4+4}{2} ,  \frac{-2+4}{2} )=(0, 1).


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\displaystyle{ m= \frac{y_2-y_1}{x_2-x_1}= \frac{-8-1}{18-0}= \frac{-9}{18}= \frac{-1}{2}.


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5 0
3 years ago
Solve the equation using the quadratic formula : x^2-10x+25=18
Sever21 [200]
x^2-10x+25=18 \\ \\x^2-10x+25-18 = 0\\ \\ x^2-10x+ 7 =0 \\ \\a=1 , b = -10 , c= 7 \\ \\ \Delta = b^{2}-4ac = (-10)^{2}-4*1*7=100-28 = 72 \\ \\\sqrt{\Delta }=\sqrt{72}= \sqrt{2*36} =\sqrt{36}*\sqrt{2} =6\sqrt{2}

x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{10- 6\sqrt{2}}{2}=\frac{2(5-3\sqrt{2})}{2}= 5-3\sqrt{2}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{10+ 6\sqrt{2}}{2}=\frac{2(5+3\sqrt{2})}{2}= 5+3\sqrt{2}


Answer : \ x= 5-3\sqrt{2} \ \ or \ \ x = 5+3\sqrt{2}


8 0
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