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koban [17]
3 years ago
15

Jenny wants to order tickets to a production of Charles Dickens’ A Christmas Carol. The ticket broker charges a one-time fee of

$15 plus $28 per ticket. The total cost of t tickets can be found using the expression 15+28t. How much will it cost Jenny to purchase 4 tickets?
Mathematics
1 answer:
Simora [160]3 years ago
4 0

$127 is the answer.. can i have a brainliest? :)

You might be interested in
The volume of a 9-inch cube is _____.
Ray Of Light [21]

Answer:

b. 729 cubed inches³

Step-by-step explanation:

A cube's area can be calculated using the length. The formula is length³.

Volume of 9-inch cube = 9³ inch

                                       = 729 cubed inches³

4 0
3 years ago
The length of the longer leg of a right triangle is
Harman [31]
A and b are legs
a^2+b^2=c^2
lets say
a>b

so
a=13+3b
c=14+3b

a^2+b^2=c^2
(13+3b)^2+b^2=(14+3b)^2
9b^2+78b+169+b^2=9b^2+84b+196
10b^2+78b+169=9b^2+84b+196
minus 9b^2 both sides
b^2+78b+169=84b+196
minus 84b both sides
b^2-6b+169=196
minus 196 both sides
b^2-6b-27=0
factor
(b+3)(b-9)=0
set to zero
b+3=0
b=-3, false, dimentions cannot be negative

b-9=0
b=9

shorter leg is 9

a=13+3b
a=13+3(9)
a=13+27
a=40

c=14+3b
c=14+27
c=41

side legnths are
9in, 40in, 41in
3 0
3 years ago
Please answer correctly !!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!
chubhunter [2.5K]

16:20

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8 0
3 years ago
In how many ways can 2 red, 2 black, 3 white and 2 blue balls be selected from 4 red, 3 black, 4 white and 8 blue balls? In how
Montano1993 [528]
From the total pool of colored balls, one can choose 2 reds, 2 blacks, 3 whites, and 2 blues in

\dbinom42\cdot\dbinom32\cdot\dbinom43\cdot\dbinom82=6\cdot3\cdot4\cdot28=2016

ways.

I'm assuming no ball of the same color is distinguishable from any other ball of the same color. So when I'm considering the possible arrangements, if I had lined up the ball as

red1 - black - red2 - ...

then this would be no different that

red2 - black - red1 - ...

So I now have 9 balls to arrange, which means there are 9!=362,880 total possible permutations of them. But order among distinct colors is assumed to not matter. This means I have to divide the total number of permutations by the number of ways I could permute balls of the same color. Then there would be a total of

\dfrac{9!}{2!\cdot2!\cdot3!\cdot2!}=7,560

ways of arranging the balls I had selected.
5 0
3 years ago
Solve for x <br> 6x+3y=54<br> 2x+y=18
butalik [34]

Step-by-step explanation:

6x+3y=54

- 2x+y=18

I'm going to be using the elimination method cause it seems easiest here. so for the elimination method u choose a variable to eliminate I chose y u could do x too if u want to. so first step would be to multiply the second equation by 3. 6x+3y=54

so now u just have to eliminate

6x+3y=54

- 6x+3y=54

because these cancel out the answer would be an infinite solution

8 0
3 years ago
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