Answer:
b. 729 cubed inches³
Step-by-step explanation:
A cube's area can be calculated using the length. The formula is length³.
Volume of 9-inch cube = 9³ inch
= 729 cubed inches³
A and b are legs
a^2+b^2=c^2
lets say
a>b
so
a=13+3b
c=14+3b
a^2+b^2=c^2
(13+3b)^2+b^2=(14+3b)^2
9b^2+78b+169+b^2=9b^2+84b+196
10b^2+78b+169=9b^2+84b+196
minus 9b^2 both sides
b^2+78b+169=84b+196
minus 84b both sides
b^2-6b+169=196
minus 196 both sides
b^2-6b-27=0
factor
(b+3)(b-9)=0
set to zero
b+3=0
b=-3, false, dimentions cannot be negative
b-9=0
b=9
shorter leg is 9
a=13+3b
a=13+3(9)
a=13+27
a=40
c=14+3b
c=14+27
c=41
side legnths are
9in, 40in, 41in
From the total pool of colored balls, one can choose 2 reds, 2 blacks, 3 whites, and 2 blues in

ways.
I'm assuming no ball of the same color is distinguishable from any other ball of the same color. So when I'm considering the possible arrangements, if I had lined up the ball as
red1 - black - red2 - ...
then this would be no different that
red2 - black - red1 - ...
So I now have 9 balls to arrange, which means there are

total possible permutations of them. But order among distinct colors is assumed to not matter. This means I have to divide the total number of permutations by the number of ways I could permute balls of the same color. Then there would be a total of

ways of arranging the balls I had selected.
Step-by-step explanation:
6x+3y=54
- 2x+y=18
I'm going to be using the elimination method cause it seems easiest here. so for the elimination method u choose a variable to eliminate I chose y u could do x too if u want to. so first step would be to multiply the second equation by 3. 6x+3y=54
so now u just have to eliminate
6x+3y=54
- 6x+3y=54
because these cancel out the answer would be an infinite solution