Answer:
try math-way
Step-by-step explanation:
Answer: To me it looks like A or D.
Step-by-step explanation: i would probably go with A because thats the only information it gave. hope this helped :)
9514 1404 393
Answer:
64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729
Step-by-step explanation:
The row of Pascal's triangle we need for a 6th power expansion is ...
1, 6, 15, 20, 15, 6, 1
These are the coefficients of the products (a^(n-k))(b^k) in the expansion of (a+b)^n as k ranges from 0 to n.
Your expansion is ...
1(2k)^6(-1/3)^0 +6(2k)^5(-1/3)^1 +15(2k)^4(-1/3)^2 +20(2k)^3(-1/3)^3 +...
15(2k)^2(-1/3)^4 +6(2k)^1(-1/3)^5 +1(2k)^0(-1/3)^6
= 64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729
Question asked: You had $207, but you are spending $2 each day. Which algebraic expression describes this situation, where d represents the number of day?
My answer: -2d+207
Because u have $207 but u r spending $2 a day that is where the -2d comes in
<h3><u>Question:</u></h3>
After the orchestra completed its program, there was a party to allow the patrons to mingle with the musicians. Kayla’s Catering provided the food, drinks, and service for the party. There were two hundred seven guests. Kayla charges $27.00 per guest for food and $10.00 per guest for drinks. To that she adds $4.98 per guest for service. What was Kayla's total bill for catering the party?
<h3><u>Answer:</u></h3>
The total bill for catering the party is $ 8689.86
<h3><u>Solution:</u></h3>
Kayla’s Catering provided the food, drinks, and service for the party
Total number of guests = 207
Charge for food for 1 guest = $ 27
Charge for drink for 1 guest = $ 10
Charge for service for 1 guest = $ 4.98
<em><u>To find: Kayla total bill for cater</u></em>
Total bill = Total number of guests(Charge for food for 1 guest + Charge for drink for 1 guest + Charge for service for 1 guest)

Thus total bill for catering the party is $ 8689.86