Can someone please answer. There is a picture. There is only one problem. Thank you so much!!!
1 answer:
Well, it doesn't exactly have what I'd call 'vertices', but
the extreme left and right points are (-5, 0) and (5, 0) .
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Answer:
61,257
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Hello,
x^3-12x²-2x+24=x²(x-12)-2(x-12)=(x-12)(x²-2)
=(x-12)(x-√2)(x+√2)
Answer:
Step-by-step explanation:
Trapezoid
Solve for area
A=44
a Base
5
b Base
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4