First let P(x) = g(x)/f(x) = x^2 - 9 / 2 - x^0.5
The domain of the nominator is any value
The domain of the denominator is
Zeros of the denominator
2-x^0.5 = 0
-x^0.5 = -2
x^0.5 = 2
x = 4
domain of x^0.5 is x >= 0
(0,4) and (4, inf)
I will sit down, if there is an open chair.
Answer:
d
Step-by-step explanation:
i dont know it just be like that
Answer:
123
Step-by-step explanation:
15 + 3 (36) = 123
