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Keith_Richards [23]
3 years ago
7

Can anybody tell me why I got the answer for rank 3

Mathematics
1 answer:
storchak [24]3 years ago
8 0
No
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Three times the smaller of two consecutive odd integers is the same as 116 less than 5 times the larger integer find the integer
Marysya12 [62]
Let x and x+2 be there integers. then
3x=5(x+2)-116
3x=5x+10-116
2x=106
x=53
numbers are 53 and 55
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How do you graph inverse functions?
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A function and its inverse are reflected over the line y = x. To graph a function and its inverse, all you have to do is graph the function and then switch all x and y values in each point to graph the inverse.
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A submarine is traveling 180 below sea level.Find the new position of the submarine after it ascends 55 feet
Marta_Voda [28]

Answer:

125 feet below sea level or -125

Step-by-step explanation:

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3 years ago
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The table gives the probability distribution of the annual rate of return on the stock of MNP Company, Inc. What is the expected
krok68 [10]
For the answer to the question above,
The expected value in percentage format is 0.2 x 15+0.4 x 20 + 0.3 x 30 + 0.1*35 = <u><em>23.5%</em></u>
The answer is <u><em>23.5%
</em></u>

I hope my answer helped you. Have a nice day ahead!
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Kryptonite is a material found on the planet Krypton and has various effects, most importantly on Superman. The most common type
Rashid [163]

Answer:

The maximum amount of red kryptonite present is 33.27 g after 4.93 hours.

Step-by-step explanation:

dy/dt = y(1/t - k)

separating the variables, we have

dy/y = (1/t - k)dt

dy/y = dt/t - kdt

integrating both sides, we have

∫dy/y = ∫dt/t - ∫kdt

㏑y = ㏑t - kt + C

㏑y - ㏑t = -kt + C

㏑(y/t) = -kt + C

taking exponents of both sides, we have

\frac{y}{t} = e^{-kt + C}  \\\frac{y}{t} = e^{-kt}e^{C} \\\frac{y}{t} = Ae^{-kt}   (A = e^{C})\\y = Ate^{-kt}

when t = 1 hour, y = 15 grams. So,

y = Ate^{-kt}\\15 = A(1)e^{-kX1}\\15 = Ae^{-k}(1)

when t = 3 hours, y = 30 grams. So,

y = Ate^{-kt}\\30 = A(3)e^{-kX3}\\30 = 3Ae^{-3k} (2)

dividing (2) by (1), we have

\frac{30}{15}  = \frac{3Ae^{-3k}}{Ae^{-k}} \\2 = 3e^{-2k}\\\frac{2}{3} = e^{-2k}

taking natural logarithm of both sides, we have

-2k = ㏑(2/3)

-2k = -0.4055

k = -0.4055/-2

k = 0.203

From (1)

A = 15e^{k} \\A = 15e^{0.203} \\A = 15 X 1.225\\A = 18.36

Substituting A and k into y, we have

y = 18.36te^{-0.203t}

The maximum value of y is obtained when dy/dt = 0

dy/dt = y(1/t - k) = 0

y(1/t - k) = 0

Since y ≠ 0, (1/t - k) = 0.

So, 1/t = k

t = 1/k

So, the maximum value of y is obtained when t = 1/k = 1/0.203 = 4.93 hours

y = 18.36(1/0.203)e^{-0.203t}\\y = \frac{18.36}{0.203}e^{-0.203X1/0.203}\\y = 90.44e^{-1}\\y = 90.44 X 0.3679\\y = 33.27 g

<u>So the maximum amount of red kryptonite present is 33.27 g after 4.93 hours.</u>

3 0
3 years ago
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