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3 years ago

How many solutions does the system have? y= -2x - 4 y= 3х + 3

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

8 0

Answer:

One solution

Step-by-step explanation:

The system has one solution and that is (-1.4, -1.2)

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A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i what is the students mistakes

Rufina [12.5K]

Answer:

1. In the multiplication of the imaginary parts, the student forgot to square of i. OR

2. The student has only multiplied the real parts and the imaginary parts.

Correct value $=22+7i$ .

Step-by-step explanation:

The given expression is

$(4+5i)(3-2i)$

A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i.

Student's mistake can be either 1 or second:

1. In the multiplication of the imaginary parts, the student forgot to square of i.

2. The student has only multiplied the real parts and the imaginary parts.

$(4+5i)(3-2i)=4\times 3+5\times (-2)i=12-10i$

Which is not correct. The correct steps are shown below.

Using distributive property, we get

$4(3-2i)+5i(3-2i)$

$4(3)+4(-2i)+5i(3)+5i(-2i)$

$12-8i+15i-10i^2$

$12+7i-10(-1)$ $[\because i^2=-1]$

$12+7i+10$

$22+7i$

Therefore, the correct value of $(4+5i)(3-2i)$ is $22+7i$ .

4 0

3 years ago

11+8q=3q-19 I need help please idk the answer

iren2701 [21]

Answer:

-6

Step-by-step explanation:

1) combine all like terms

(bring 3q to the left and 11 to the right so you can combine the like terms)

(doing that will make 3q negative and 11 negative since your moving them so their sign changes as well)

8q-3q=-19-11

5q=-30

Q=-6

Hope this helps

4 0

3 years ago

(02.06)How many pounds are there in 2 and 3 over 4 tons? (1 ton = 2000 pounds)

Veseljchak [2.6K]

Answer:

5500 pounds

Step-by-step explanation:

if you mean 2¾

in 2 tons there's 4000 pounds

in ¾ of a ton there is 1500 pounds

4000 + 1500 = 5500 pounds

3 0

3 years ago

Rewrite this standard form quadratic equation into vertex form by completing the square. Upload your work here to show your thin

Alex787 [66]

Solution :

Given the equation :

$y = x^2 - 6x+3$

$y=1(x^2 - 6x +n)+3$

$n = \left(\frac{b}{2}\right)^2$

$n = \left(\frac{6}{2}\right)^2$

n = 9

$y=1(x^2 - 6x +9-9)+3$

$y=1(x^2 - 6x +9)-9+3$

$y=1(x-3)^2- 6$

Therefore the vertex form of $y = x^2 - 6x+3$ is $y=1(x-3)^2- 6$ .

3 0

3 years ago

All ir rational numbers are rational numbers

patriot [66]

Answer:

Step-by-step explanation:

false

irrational numbers cannot be rational

8 0

3 years ago