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Molodets [167]
2 years ago
7

Which one is idk what it is giving brainliest

Chemistry
2 answers:
Salsk061 [2.6K]2 years ago
8 0

Answer:

B or C

Explanation:

I don't really know sorry.

Nata [24]2 years ago
8 0

Answer:

D

Explanation:

I think D I also took the test.

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How many moles of a gas sample are in a 20.0 L container at 373 K and 203 kPa? The gas constant is 8.31 L-kPa/mol-K. 0.33 moles
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We need to use the ideal gas formula--> PV= nRT 
P, pressure= 203 kPa
V, volume= 20.0 Liters
n, moles= ?
R, constant= <span>8.31 L-kPa/mol-K
T, temperature= 373 K

now, lets plug these values into the formula

(203)(20.0)= (n)(8.31)(373)

n= 1.31 moles</span>
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3 years ago
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Given the following sets of values, calculate the unknown
weqwewe [10]

Answer:

3.91 L

Explanation:

Using the ideal gas law equation as follows:

PV = nRT

Where:

P = pressure (atm)

V = volume (L)

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T = temperature (K)

Based on the information given in this question,

P = 5.23 atm

V= ?

n = 0.831 mol

T = 27°C = 27 + 273 = 300K

Using PV = nRT

V = nRT/P

V = (0.831 × 0.0821 × 300) ÷ 5.23

V = 20.47 ÷ 5.23

V = 3.91 L

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