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Rus_ich [418]
3 years ago
6

Which statement about these two triangles is true?

Mathematics
1 answer:
Feliz [49]3 years ago
8 0
It is th top right answer because AB = DE but the others are not but length doesn't effect the angles of abcdef
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What equation is graphed in this figure?
aniked [119]

Based on the graph, the slope is -3, and the y-intercept is 1. So your equation should be:

y = -3x + 1

The answer is C

y + 2 = -3(x - 1)

y + 2 = -3x + 3

y = -3x + 1

5 0
3 years ago
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Use f’( x ) = lim With h ---> 0 [f( x + h ) - f ( x )]/h to find the derivative at x for the given function. 5-x²
beks73 [17]
<h2>Answer:</h2>

The derivative of the function f(x) is:

                 f'(x)=-2x

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as:

f(x)=5-x^2

We have:

f(x+h)=5-(x+h)^2\\\\i.e.\\\\f(x+h)=5-(x^2+h^2+2xh)

( Since,

(a+b)^2=a^2+b^2+2ab )

Hence, we get:

f(x+h)=5-x^2-h^2-2xh

Also, by using the definition of f'(x) i.e.

f'(x)= \lim_{h \to 0} \dfrac{f(x+h)-f(x)}{h}

Hence, on putting the value in the formula:

f'(x)= \lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-(5-x^2)}{h}\\\\\\f'(x)=\lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-5+x^2}{h}\\\\i.e.\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2-2xh}{h}\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2}{h}+\dfrac{-2xh}{h}\\\\f'(x)=\lim_{h \to 0} -h-2x\\\\i.e.\ on\ putting\ the\ limit\ we\ obtain:\\\\f'(x)=-2x

      Hence, the derivative of the function f(x) is:

          f'(x)=-2x

3 0
3 years ago
Read 2 more answers
Measuring Circles: Question 1
andreev551 [17]

Answer:10.51inches

Step-by-step explanation:

circumference=66

Radius=circumference ➗ (2xπ)

Radius=66 ➗ (2x3.14)

Radius=66 ➗ 6.28

Radius=10.51inches

7 0
3 years ago
---- PLEASE HELP &lt;3 .. with steps :( &lt;3
Zielflug [23.3K]

1) 6, 18, 54

2) 5/3, 14/9, 41/27

3) 1.5, 2.5, 2.5

Step-by-step explanation:

1)

The function that we have in this problem is

g(x)=3x

We want to find the first 3 iterations.

The initial value is:

x = 2

To find the value of the 1st iteration, we just substitute this value into the expression of the function, and we get:

g_1(x)=3x=3\cdot 2 = 6

The to find the value of the 2nd iteration, we just substitute this value into the expression of the function, and we get:

g_2(x)=3\cdot g_1(x)=3\cdot 6 = 18

Finally, the 3rd iteraction is given by:

g_3(x)=3g_2(x)=3\cdot 18=54

2)

Here in this problem the function that we have to use is

g(x)=\frac{1}{3}x+1

The initial value is

x=2

So the first iteration is given by

g_1(x)=\frac{1}{3}\cdot 2 + 1 = \frac{5}{3}

To find the 2nd iteration, we substitute this value into g(x) again:

g_2(x)=\frac{1}{3}g_1+1=\frac{1}{3}\cdot \frac{5}{3}+1=\frac{5}{9}+1=\frac{14}{9}

Finally, to find the 3rd iteration, we substitute this value into g(x) again:

g_3(x)=\frac{1}{3}\cdot \frac{14}{9}+1=\frac{14}{27}+1=\frac{41}{27}

3)

The function in this problem is

g(x)=-|x-2|+3

The initial value is

x = 0.5

So, the first iteration is:

g_1(x)=-1|0.5-2|+3=-1|-1.5|+3=-1\cdot 1.5 +3=-1.5+3=1.5

The second iteration is given by

g_2(x)=-|g_1-2|+3=-|1.5-2|+3=--0.5+3=2.5

Finally, the 3rd iteration is

g_3(x)=-|g_2-2|+3=-|2.5-2|+3=-0.5+3=2.5

5 0
3 years ago
A number added to one third of itself equals 12 . what is the number​
Drupady [299]

Answer:

9

Step-by-step explanation:

x+1/3x=12

(3x+1x)/3=12

4x/3=12

4x=12×3

4x=36

x=36/4

x=9

8 0
3 years ago
Read 2 more answers
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