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2 years ago

F(x) = -x² + 4x - 1 find the value of f(x) if x = 0

Mathematics

1 answer:

ollegr [7]2 years ago

8 0

Answer:

-1

Step-by-step explanation:

Given,

f(x) = -x² + 4x - 1 and x = 0

Putting the value of x we get,

f(0)= $-0^{2}$ + (4 X 0) - 1

= -0+0-1

=-1

∴f(x)= -1

So, the required value is -1

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tankabanditka [31]

Answer:

Step-by-step explanation:

hello,

i advice you check the question again if it is GF( $2^{4}$ ) or GF(24). i believe the question should rather be in this form;

multiplication in GF( $2^{4}$ ): Compute A(x)B(x) mod P(x) = $x^{4}$ + $x$ +1, where A(x)= $x^{2}$ +1, and B(x)= $x^{3} + x+1$ .

i will solve the above question and i believe with this you will be able to solve any related problem.

A(x)B(x)= $(x^{2} +1) (x^{3}+x+1) mod (x^{4}+x+1 ) = (x^{5} +x^{3}+x^{2} ) + (x^{3}+x+1 ) mod (x^{4} + x+1 )$

= $x^{5}+2x^{3} +x^{2} + x + 1 mod(x^{4}+x+1 )$

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please note that the division by the modulus above we used

$\frac{x^{5}+2x^{3}+x^{2} +1 }{x^{4}+x+1}= x+\frac{2x^{3} +1}{x^{4}+x+1}$

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2 years ago

Describe the graph of the function f(x) = 2x^3 +14x^2 +13x +6. Include the y-intercept, x-intercepts, and the shape of the graph

vovikov84 [41]

$f(x) = 2x^{3} + 14x^{2} + 13x + 6$

The graph is attached below.

In order to find the y-intercept, check the graph and see where it hits the y-axis, so in this case the y-intercept would be at (0,6).

To find the x-intercept, check the graph and see where it hits the x-axis, and here it hits at x = -6.

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