Subtract
\frac{3n+2}{n-4}-\frac{n-6}{n+4}
2 answers:
Answer:
I think you meant to put: ((3n+2)/n+4)-(n-6)/n+4
Step-by-step explanation:
the answer would be 2n-4/n+4
leave the denominators alone
the numerator would be:
3n+2-n-6=2n-4
so that just simplifies to (2n-4)/n+4
hope this helps
(3n+2)/(n-4) - (n-6)/(n+4)
common denominator (n-4)(n+4)
{(n+4)(3n+2)-(n-4)(n-6)}/{(n-4)(n+4)}
Use the foil method:
{(3n²+14n+8)-(n²-10n+24)}/{(n-4)(n+4)}
distribute negative sign:
{(3n²+14n+8-n²+10n-24)}/{(n-4)(n+4)}
subtract:
(2n²+24n-16)/{(n-4)(n+4)}
take out 2:
2{n²+12n-8}/{(n-4)(n+4)}
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