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solmaris [256]
3 years ago
7

A pair of corresponding side of two similar pentagons have length of 12cm and 28cm

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
5 0
The ratio of their areas = 12^2 / 28^2
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B- 6x(x+2)

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Step-by-step explanation:

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2 years ago
John has a circular pool that has a radius of 7 feet. What is the area of his pool? Please use the formula sheet to assist you w
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153.86 square feet

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8 0
2 years ago
Here is the questions sorry
xxMikexx [17]

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Step-by-step explanation:

6 0
3 years ago
I'm really lost on this problem
Alenkinab [10]
Since you need a little bit of trigonometry to solve this problem,
I'm pretty sure you've had a little bit of trigonometry in class before
you were assigned to solve this problem.

-- The shaded triangle comes from taking the equilateral triangle and
either folding it in half or cutting it in half.

-- The base that the new triangle is standing on is 1/2 the base of the
equilateral triangle, so it's 7 cm long.

-- The acute angle at the right end of the base is the same as it was in
the equilateral triangle . . . 60 degrees.

--  The tangent of 60 degrees is (opposite side)/(adjacent side) = x / 7 cm

              tan(60) = x/7

-- Multiply each side of this little equation by 7 :   7 tan(60) = x
 
If you don't have the tangent of 60 degrees in your pocket, you can
find it with your calculator.  Multiply it by 7, and Shazam, you know 'x' .
5 0
3 years ago
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