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Veronika [31]
3 years ago
13

P equals to 2x + 3 all over 3x - 2 Express the following equation​

Mathematics
1 answer:
Gekata [30.6K]3 years ago
4 0

Answer:

The equation is;

p = (2x + 3)/(3x-2)

Step-by-step explanation:

Here, we want to express the given equation written in words

We have this as;

p = (2x + 3)/(3x-2)

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HELPPPPPPPP PLS!!!!!!!
VikaD [51]

Answer:

(15x + 120) ft³

Or

15(x + 8) ft³

Step-by-step explanation:

The prism can be decomposed into a rectangular prism and a triangular prism

The volume of the prism = volume of the rectangular prism + volume of the triangular prism

✔️Volume of rectangular prism = L*W*H

L = 5 ft

W = 4 ft

H = 6 ft

Volume = 5*4*6 = 120 ft³

✔️Volume of triangular prism = ½*b*h*l

b = x ft

h = 6 ft

l = 5 ft

Volume = ½*x*6*5 = 15x ft³

✔️Volume of the prism = (15x + 120) ft³

6 0
3 years ago
The mean time required to repair breakdowns of a certain copying machine is 93 minutes. The company which manufactures the machi
Sonja [21]

Answer:

t=\frac{88.8-93}{\frac{26.6}{\sqrt{73}}}=-1.349    

p_v =P(t_{(72)}  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can't concluce that the true mean is less than 93 min at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=88.8 represent the sample mean

s=26.6 represent the sample standard deviation for the sample  

n=73 sample size  

\mu_o =93 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean i lower than 93 min, the system of hypothesis would be:  

Null hypothesis:\mu \geq 93  

Alternative hypothesis:\mu < 93  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{88.8-93}{\frac{26.6}{\sqrt{73}}}=-1.349    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=73-1=72  

Since is a one side test the p value would be:  

p_v =P(t_{(72)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can't concluce that the true mean is less than 93 min at 5% of signficance.  

5 0
3 years ago
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