Answer: A quadrilateral has vertices A(3, 5), B(2, 0), C(7, 0), and D(8, 5). Find:
You can see that vectors and This means that opposite sides are parallel and option B is false.
Find the lengths of all sides:
As you can see the lengths of opposite sides are equal, but all lengths are not equal. Therefore, the last option D is false.
Now check whether angles A and B are perpendicular:
The dot products are not equal to zero, then angles A and B are nor right. This means that option C is false and option A is correct (ABCD is a parallelogram with non-perpendicular adjacent sides
AKA your correct awnser choice is A :)✨
Answer: Choice C) When you solve for the variable, you will end up with a false statement, like 0 = 2, for an equation with no solution. You will end up with a true statement, like 2 = 2 for an equation with infinitely many solutions.
For example, let's say we had the equation x = x+2. Subtracting x from both sides leads to 0 = 2 which is a false statement. No matter what we replace x with, the equation x = x+2 is always false. That's why we don't have any solutions here.
For an equation like x + 2 = x + 2, subtracting x from both sides leads to 2 = 2 which is always true. A true equation is one where the same number is on both sides. No matter what we replace x with, the equation will be true. Therefore, there are infinitely many solutions.
It shows a change in growth, and has a percentage rate that is positive, I .
Answer:
{x,y} = {-2,-3}
Step-by-step explanation:
System of Linear Equations entered :
[1] -9x + 4y = 6
[2] 9x + 5y = -33
Graphic Representation of the Equations :
4y - 9x = 6 5y + 9x = -33
Solve by Substitution :
// Solve equation [2] for the variable y
[2] 5y = -9x - 33
[2] y = -9x/5 - 33/5
// Plug this in for variable y in equation [1]
[1] -9x + 4•(-9x/5-33/5) = 6
[1] -81x/5 = 162/5
[1] -81x = 162
// Solve equation [1] for the variable x
[1] 81x = - 162
[1] x = - 2
// By now we know this much :
x = -2
y = -9x/5-33/5
// Use the x value to solve for y
y = -(9/5)(-2)-33/5 = -3
