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Anna71 [15]
3 years ago
6

Customers arrive randomly at a service point at an average rate of 30 per hours.Assuming a Possition distibution,calculate the p

robability that
a.no customers arrive in a particular minute.
b.exactly one customer arrives in five minutes.
c.at most one customer arrive in ten minutes.​
Mathematics
1 answer:
inna [77]3 years ago
4 0

Answer:

honestly man I say go with c

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Stolb23 [73]

Answer:

#4:so you find out the y and the x next to the 2 and if the answer is 10 you got it right  then you add it to this to the graph.

#5: i think i need help on this one

Step-by-step explanation:

hope this helps

5 0
2 years ago
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Can someone please help?
Alika [10]

Answer:

A. mean 71.33, median 86, mode 90 90 100 100, range 55

B. mean 79.41, median 36.5, mode 90, range 60

c. mean 73.16, median 2, mode 75 75 80 80, range 45

Step-by-step explanation:

mean is the average so add all numbers then divide by the number of number

mode is the number that is often seen

range subtract the smallest from largest or the other way around

median the middle number when lined all number from less to biggest  

4 0
2 years ago
Express 45 minutes as a fraction of 1 hour ​
Pepsi [2]

Answer:

\frac{3}{4}

Step-by-step explanation:

There are 60 minutes in 1 hour

To express as a fraction

\frac{45}{60}

Divide numerator/denominator by 15

\frac{45}{60} = \frac{3}{4}

8 0
3 years ago
Math question plz help
Svetach [21]

Answer:

Yes they are.

Because:

As said in the rules you have to keep the bases and add the exponents.

7 0
2 years ago
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Suppose Burger King has run a major advertising campaign in the hopes of increasing monthly sales. To investigate the effectiven
Alexxandr [17]

Answer:

The right answer is:

a.H0: μd = 0; H1: μd > 0

Step-by-step explanation:

The claim that want to be tested is that the sales were significantly increased after the commercial, indicanting that the advertisement campaign was effective.

This claim is usually expressed in the alternative hypothesis as it has to have enough evidence to prove that it is true.

Then, the alternative hypothesis H1 should state that the difference (sales after - sales before) is higher than 0.

The null hypothesis would state that the difference is not significantly different from 0, or, in other words, that the sales are the same before and after and that the variation is due to pure chance.

Then, the null hypothesis H0 would state that the difference is equal to 0.

The right answer is:

a.H0: μd = 0; H1: μd > 0

4 0
3 years ago
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