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Anna71 [15]
3 years ago
6

Customers arrive randomly at a service point at an average rate of 30 per hours.Assuming a Possition distibution,calculate the p

robability that
a.no customers arrive in a particular minute.
b.exactly one customer arrives in five minutes.
c.at most one customer arrive in ten minutes.​
Mathematics
1 answer:
inna [77]3 years ago
4 0

Answer:

honestly man I say go with c

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Solve for the equation, show all your work. This is an absolute value equation. You need to show both equations and the work for
VMariaS [17]

Answer:

x=-1 or 7

Step-by-step explanation:

We use casework on when 3x-9=12 and when 3x-9=-12.

For the first case, 3x-9=12, we add 9 to both sides to get

3x=21.

Dividing both sides by 3 gives

x=7.

For the second case, 3x-9=-12, we add 9 to both sides to get

3x=-3.

Dividing both sides by 3 gives

x=-1.

Checking both cases, we plug in x=7 and x=-1.

For the first case, we have |3(7)-9|=|21-9|=|12|=12,  which satisfies the equation.

For the second case, we have |3(-1)-9|=|-3-9|=|-12|=12, which also satisfies the equation.

This gives us two solutions to the equation; x=7 and x=-1.

4 0
2 years ago
Calculate the arithmetic sequence in which a9=17 and the common difference is d=-2.1
jek_recluse [69]

Answer:

S_{31}=71.3


Step-by-step explanation:

The nth term of an arithmetic sequence is given by the formula,

U_n=a_1+(n-1)d


We were given that the 9th term is 17.


\Rightarrow 17=a_1+(9-1)(-2.1)


\Rightarrow 17=a_1+(8)\times(-2.1)


\Rightarrow 17=a_1-\frac{84}{5}


\Rightarrow 17+\frac{84}{5}=a_1


\Rightarrow a_1=\frac{169}{5}


The sum of the first n-terms is given by the formula,


S_n=\frac{n}{2}(2a_1+(n-1)d)


To find S_{31}, we substitute n=31, a_1=\frac{169}{5} and d=-2.1.


\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(31-1)(-2.1))


\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(30)(-2.1))



\Rightarrow S_{31}=\frac{31}{2}(\frac{23}{5})


\Rightarrow S_{31}=\frac{713}{10}


\Rightarrow S_{31}=71.3


The correct answer is D















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A father walks 36 miles in 12 hours while his son covers the same distance on a bicycle at twice the father's rate of speed. At
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it would be d.)54 miles

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