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Jlenok [28]
3 years ago
15

Which is equivalent to 216 Superscript one-third?

Mathematics
2 answers:
olga2289 [7]3 years ago
8 0

Answer:

6

Step-by-step explanation:

216 raised to the one third power is the same as asking for the cubed root of 216. 6x6x6=216

hope this helps :)

Tems11 [23]3 years ago
7 0

Answer:

6

Step-by-step explanation:

6x6x6=216

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Solve<br> x2 - 8x + 14 = 2x - 7
BabaBlast [244]

Answer:

x=7, x=3

Step-by-step explanation:

             x^{2} -8x+14=2x-7

x^{2} -8x-2x+14+7=0

            x^{2} -10x+21=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x= \frac{-b\pm \sqrt{b^2-4ac}}{2a}

positive

x=\frac{-\left(-10\right)+\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}

x=7

negative

x=\frac{-\left(-10\right)-\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}

x=3

7 0
3 years ago
A salesperson contacts eight potential customers per day. From past experience, we know that the probability of a potential cust
AlexFokin [52]

Answer:

(a) The probability the salesperson will make exactly two sales in a day is 0.1488.

(b) The probability the salesperson will make at least two sales in a day is 0.1869.

(c) The percentage of days the salesperson does not makes a sale is 43.05%.

(d) The expected number of sales per day is 0.80.

Step-by-step explanation:

Let <em>X</em> = number of sales made by the salesperson.

The probability that a potential customer makes a purchase is 0.10.

The salesperson contacts <em>n</em> = 8 potential customers per day.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={8\choose x}0.10^{x}(1-0.10)^{8-x};\ x=0,1,2,3...

(a)

Compute the probability the salesperson will make exactly two sales in a day as follows:

P(X=2)={8\choose 2}0.10^{2}(1-0.10)^{8-2}\\=28\times 0.01\times 0.5314\\=0.1488

Thus, the probability the salesperson will make exactly two sales in a day is 0.1488.

(b)

Compute the probability the salesperson will make at least two sales in a day as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-{8\choose 0}0.10^{0}(1-0.10)^{8-0}-{8\choose 1}0.10^{1}(1-0.10)^{8-1}\\=1-0.4305-0.3826\\=0.1869

Thus, the probability the salesperson will make at least two sales in a day is 0.1869.

(c)

Compute the probability that a salesperson does not makes a sale is:

P(X=0)={8\choose 0}0.10^{0}(1-0.10)^{8-0}\\=8\times 1\times 0.4305\\=0.4305

The percentage of days the salesperson does not makes a sale is,

0.4305 × 100 = 43.05%

Thus, the percentage of days the salesperson does not makes a sale is 43.05%.

(d)

Compute the expected number of sales per day as follows:

E(X)=np=8\times 0.10=0.80

Thus, the expected number of sales per day is 0.80.

7 0
3 years ago
Simplify (7)(-6). need help
dexar [7]
As simple as it can go is As it's multiplied out form, which is -42.
5 0
4 years ago
Read 2 more answers
(-6127) + _____. = (-6127)
vredina [299]

Answer:

(-6127) + 0 = (-6127)

(+18) + 2 = (+20)

(+27) - 7 = (+20)

(+63) + (-13) = (+50)

(+21) - 4 = (+17)

Step-by-step explanation:

5 0
3 years ago
5 . 9 × ____ = 73.16 which is the missing factor?
ladessa [460]

Answer:

12.4

Step-by-step explanation:

73.16/5.9

3 0
3 years ago
Read 2 more answers
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