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Black_prince [1.1K]
3 years ago
12

The length of a new rectangular playing field is 6 yards longer than double the width. If the perimeter of the rectangular playi

ng field is 294 yards what are the dimensions?
Mathematics
1 answer:
Andru [333]3 years ago
4 0

Answer:

width = 47

Length = 100

Step-by-step explanation:

The perimeter of the rectangle has the formula

P = 2(L + W)

P = 2L + 2W

Length = 6 yards longer than double it's width.

Mathematically,

length = 6 + 2W

We put this into the formula for perimeter

P = 2(6+2W)+2W

294 = 12+4W+2W

294 = 12+6W

Collect like terms

294-12 = 6W

282 = 6w

Divide through by 6

W = 282/6

W = 47

This is the width

Remember length = 6 + 2(W)

So

Length = 6+2(47)

= 6+94

= 100

Width = 47

L = 100

These are the dimensions

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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- Switch the two terms of the right hand side

∴ y = 4 -  \frac{x}{2}

The equation of Grant's path is y = 4 -  \frac{x}{2}

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