There are 2 ways that spring to mind.
One is to use the definition of the derivative at a point:
In this case, 
and 
. Then
- - -
If you don't know about derivative yet (I would think you do, considering this is for a midterm in AP Calc, but I digress), the other way is to rely on algebraic manipulation. Multiply the numerator and denominator by the conjugate of the numerator to get
This is continuous at 
, so the limit is the value of the expression at :
Answer:
Step-by-step explanation:
The parent function here is y = log x, where 10 is the base.
The derivative of y = log x is dy/dx = (ln x) / ln 10.
The derivative of y = log (ax+b) is found in that manner, but additional steps are necessary: differentiate the argument ax + b:
The derivative with respect to 10 of log (ax + b) is:
dy/dx = [ 1 / (ax + b) ] / [ ln 10 ] *a, where a is the derivative of (ax + b).
Alternatively, we could express the answer as
dy/dx = [ a / (ax + b) ] / [ ln 10 ]
<h3><u>The value of the smaller number is 31.</u></h3><h3><u>The value of the larger number is 43.</u></h3>
y = 12 + x
y + x = 74
Since we have a value for y, we can plug it into the second equation
12 + x + x = 74
Subtract 12 from both sides.
x + x = 62
Combine like terms.
2x = 62
Divide both sides by 2.
x = 31
Now that we have a value of x, we can plug it into the original equation to get a value for y.
y = 12 + 31
y = 43
Answer:
Step-by-step explanation:
We have been given that point A has the coordinates(2,5) point B has the coordinates (6,17).
To find the length of segment AB we will use distance formula.
Upon substituting coordinates of point A and point B in distance formula we will get,
Therefore, the length of segment AB is .
