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3 years ago

Factor -3bk 2 + 9bk - 6b

1 answer:

8 0

First you do -3bk+9bk and that equals 6bk then since there are no more like terms the experssion would be simplified into 6bk+2-6b
HOPE THAT HELPED!

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Elsa's magic wand can cast 53 spells. Her wand can cast 17fewer spells than her sister Anna's wand, which is a little bigger and

Mademuasel [1]

Answer:

<em> Anna's wand can cast 70 spells</em>

Step-by-step explanation:

Elsa's wand can cast 53 spells

her wand casts 17 fewer cells than her sister Anna's

Amount of spells cast by Anna's wand = ?

We write the question down in the form of an equation

$x - 17 = 53$

where $x$ is the amount of spells Anna's wand can cast.

we then proceed to solve by collecting like terms to different sides of the equation. We'll have

$x = 53 + 17$

which leaves us with

$x = 70$

This means that<em> Anna's wand can cast 70 spells.</em>

4 0

3 years ago

Jane gets paid $120 for 8 hours. How much does she get paid an hour?

AleksAgata [21]

Answer:

$15 an hour

Step-by-step explanation:

To find this, we divide 120 by 8.

120 ÷ 8 = 15

So Jane gets $15 an hour

I hope this helped, please mark Brainliest, thank you!

8 0

3 years ago

Can someone please help me its urgent!!!!!!!!!!<br> 3x + 11 = 3x - 11

user100 [1]

Answer:

$\Large\boxed{\mathsf{\Rightarrow NO\quad SOLUTIONS}}$

Step-by-step explanation:

<h3><u>TO SOLVE:</u></h3>

Isolate by the x on one side of the equation.

<h3><u>SOLUTIONS:</u></h3>

First, subtract 3x from both sides.

$\displaystyle \Rightarrow \mathsf{3x+11-3x=3x-11-3x}}$

Solve.

$\displaystyle \mathsf{11=-11}$

Sides are NOT equal.

$\Large\boxed{\mathsf{\Rightarrow THERE \quad ARE \quad NO \quad SOLUTIONS}}}$

Therefore, there are no solutions.

6 0

3 years ago

3 groups of a number plus 2

nikklg [1K]

X times x times x +2

4 0

2 years ago

A particle moves so that r(t) = ati + b sin atj. Show that the magnitude of the acceleration of the particle is proportional to

ValentinkaMS [17]

Answer:

Step-by-step explanation:

Given

Position of particle is $r(t)=at\hat{i}+b\sin (at)\hat{j}$

i.e. distance from x axis is $b\sin (at)---1$

Distance from y axis at

velocity is given by $v=\frac{\mathrm{d} r}{\mathrm{d} t}$

$v=a\hat{i}+ba\cos (at)\hat{j}$

Similarly acceleration is given by

$a=\frac{\mathrm{d} v}{\mathrm{d} t}$

$a=0\hat{i}-a^2b\sin (at)\hat{j}$

Magnitude of acceleration is $=\sqrt{(-a^2b\sin (at))^2}$

$=a^2b\sin (at)----2$

From 1 and 2 we can see that

Magnitude of acceleration is proportional to distance from x axis

$a\propto distance\ from\ x-axis$

5 0

3 years ago

Read 2 more answers