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3 years ago

HELP PLEASE i give brainliest

Mathematics

2 answers:

Valentin [98]3 years ago

8 0

Answer:

find out the answere

Step-by-step explanation:

hope this helps you get the answere

UNO [17]3 years ago

6 0

Given point M (1,3) and the equation, y = kx + 1:

I started by plotting point M on the graph at (1, 3).

Next, given the equation, y = kx + 1, it means that the y-intercept is (0 , 1). That’s where I plotted the next point—along the y-axis.

By definition, the y-intercept is the point on the graph where it crosses the y-axis, and has coordinates (0, b). Therefore, (0, 1) is the y-intercept, and its y-coordinate, 1, is given by the equation, y = kx + 1.

Attached is a screenshot of the graphed line.

Please mark my answers as the Brainliest if you find my explanations helpful :)

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Point P is the center of the circle below. What is the exact area

Ber [7]

Answer:

192π unit²

Step-by-step explanation:

Given that :

Radius = 24

Area of circle = πr²

Area = π*24²

Area = 576π in²

The Shaded area is 120°

Entire Circumference = 360°

Hence, shaded area = 120°/ 360° = 1/ 3 of the area

1/3 * 576π in²

= 192π unit²

5 0

2 years ago

Please help me on this

Eduardwww [97]

To multiply a fraction, you simply multiply across the top and across the bottom.

-3 *-4 = 12
5 * 7 = 35

Final Answer: 12/35

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3 years ago

200/100=8/x (and this

morpeh [17]

Answer:

x=4

Step-by-step explanation:

7 0

3 years ago

Find the median of -12/4, 18/5, -25,1/5,10

sashaice [31]

Arrange from smallest to largest
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4 0

3 years ago

Od 2 ( 2 7 1-3 1 3 1-2 6:1-6 b = d = IDONE

Lena [83]

Answer:

$a = \boxed{1},\: b=\boxed{0}\\\\c=\boxed{0},\: d=\boxed{1}$

Step-by-step explanation:

$\begin{bmatrix} 2 & 7\\\\1 & 3\end{bmatrix}\:\begin{bmatrix} -3 & 7\\\\1 & -2\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}$

Multiply both the matrices on left side, we find:

$\begin{bmatrix} 2(-3)+7(1) & 2(7)+7(-2)\\\\1(-3)+3(1) & 1(7)+3(-2)\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}$

$\rightarrow\begin{bmatrix} -6+7 & 14-14\\\\-3+3 & 7-6\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}$

$\rightarrow\begin{bmatrix} 1 & 0\\\\0 & 1\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}$

Comparing the corresponding elements of both the matrices on both sides, we find:

$a = \boxed{1},\: b=\boxed{0},\:c=\boxed{0},\: d=\boxed{1}$

7 0

2 years ago