Solve for xif 2(5 +252 =48.

Serggg [28]

So your gonna Multiply each term in the first parentheses by each term in the second parentheses “ -5x5-5i-5x2i-2ix i ” than multiply the numbers “ -25 -5i -5x2i -2ixi ” that’s your answer!

8 0

3 years ago

Kathy dropped a snowball from a building that is 39.2 meters tall. The equation t2 = 39.29.8 represents the amount of time, in s

DIA [1.3K]

Answer:

We note that the equation that is compatible with the given equation is the kinematic equation of free fall where;

t² = 39.2 × 2/9.81

From which we have;

The time it takes the snowball to reach the ground is approximately 2.83 seconds

Step-by-step explanation:

The height of the building from which the ball is dropped, h = 39.2 m

The equation of the dropped a snowball, is given as follows;

t² = 39.2 × 9.8

Using the From the equation of free fall, we have;

s = u·t + 1/2·g·t²

Where;

u = The initial velocity = 0 m/s

t = The time of flight

g = The acceleration due to gravity = 9.81 m/s²

Therefore, we get;

∴ s = The height from which the snowball is dropped = 39.2 m

Therefore, we get;

39.2 = 0×t + 1/2×9.81×t²

∴ t² = 39.2 × 2/9.81 ≈ 7.99

t = √(7.99) ≈ 2.83

The time it takes the snowball to reach the ground, t ≈ 2.83 s.

8 0

3 years ago

A projectile is fired with muzzle speed 250 m/s and an angle of elevation 45° from a position 30 m above ground level. Where doe

qaws [65]

The projectile's horizontal and vertical positions at time $t$ are given by

$x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ\,t$

$y=30\,\mathrm m+\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ\,t-\dfrac g2t^2$

where $g=9.8\dfrac{\rm m}{\mathrm s^2}$ . Solve $y=0$ for the time $t$ it takes for the projectile to reach the ground:

$30+\dfrac{250}{\sqrt2}t-4.9t^2=0\implies t\approx36.2458\,\mathrm s$

In this time, the projectile will have traveled horizontally a distance of

$x=\dfrac{250\frac{\rm m}{\rm s}}{\sqrt2}(36.2458\,\mathrm s)\approx6400\,\mathrm m$

The projectile's horizontal and vertical velocities are given by

$v_x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ$

$v_y=\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ-gt$

At the time the projectile hits the ground, its velocity vector has horizontal component approx. 176.77 m/s and vertical component approx. -178.43 m/s, which corresponds to a speed of about $\sqrt{176.77^2+(-178.43)^2}\dfrac{\rm m}{\rm s}\approx250\dfrac{\rm m}{\rm s}$ .

7 0

3 years ago

If the sum of two numbers is 15 and their product is 50 what are they

Westkost [7]

Xy = 50
x + y = 15

x = 15 - y

xy = 50

(5 - y)y = 50

5y - y^2 = 50

y^2 - 5y + 50 = 0

(y - 5)(y - 10) = 0

y - 5 = 0 or y - 10 = 0

y = 5 or y = 10

x + y = 15

For y = 5:

x + 5 = 15

x = 10

For y = 10

x + 10 = 15

x = 5

Answer: the numbers are 5 and 10.

5 0

3 years ago

State whether the given measurements determine zero, one, or two triangles.

ohaa [14]

Answer:

One

Step-by-step explanation:

Find the value of B

Applying the law of sines

$\frac{a}{sin(A)}$ = $\frac{b}{sin(B)}$