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PIT_PIT [208]
3 years ago
7

Write an equation for “the value of m times the value of n”

Mathematics
1 answer:
NeX [460]3 years ago
7 0

Answer:m(n)

Step-by-step explanation:


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X2 - 6x + 9<br> help solve
Ulleksa [173]

Answer:

3

lazy approach was with a graphic plotting program, but you can also calculate it. with the pq-formula.

p = -6

q = 9

x = -p/2 +- sqrt( (p/2)² - q)

x = -(-6)/2 +- sqrt ( (-6/2)² - 9)

x = 3 +- sqrt(9-9)

x = 3 +- sqrt(0)

x = 3 +- 0

x = 3

4 0
3 years ago
Read 2 more answers
Can anyone help me with my homework
eimsori [14]
1- B
2- G
3- H
4- A

I hope its good for you
3 0
3 years ago
1. Jane saved up 20 coins, all nickels and
kompoz [17]

Answer:

10 nickels and 10 quarters

Step-by-step explanation:

Given

Number of coins: 20

Vaiue of coins = $3.00

Required

Number of Nickels and Quarters;

<em>Let N =Nickels and Q =Quarters</em>

The total coins is represented as:

N + Q = 20

1 nickel is equivalent to $0.05 and 1 quarter is equivalent to $0.25; So

0.05N + 0.25Q = 3

Make N the subject of formula in the first equation

N = 20 - Q

Substitute this in the second equation

0.05(20 - Q) + 0.25Q = 3

1 - 0.05Q + 0.25Q = 3

Collect like terms

-0.05Q + 0.25Q = 3 - 1

0.2Q = 2

Multiply both sides by 5

5 * 0.2Q = 2 * 5

Q = 10

Recall that N = 20 - Q

N = 20 - 10

N = 10

6 0
3 years ago
EASY FOR PEOPLE THAT KNOW HOW TO DO MATH, HELP NEEDED
SIZIF [17.4K]

Answer:

1 and 5/24 gallon left

Step-by-step explanation:

https://www.slader.com/discussion/question/mark-wants-to-paint-a-mural-he-has-113-gallons-of-yellow-paint-114-gallons-of-green-paint-and-78-g-2/

its a reliable link

3 0
3 years ago
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Can you help me with this problem please
Over [174]

Remark

I think you want us to do both 3 and 4


Three

QR is 4 points going left from the y axis + 2 points going right from the y axis.

QR = 6 units long.


RT is 4 units above the x axis and 3 units below the x axis

RT = 7 units long


TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.


Problem 4

You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.


Area = (b1 + b2)*h/2


Givens

B1 = QR = 6

B2 = UT + TS = 6 + 3 = 9

h = RT = 7


Area

Area = (6 + 9)*7/2

Area = 15 * 7 / 2

Area = 52.5


Comment

You could break this up into a rectangle + a triangle

Find the area of QRTU and add the Area of triangle RTS


<em>Area of the rectangle </em>= L * W

L = RT = 7

W = QR = 6

Area = 7 *6 = 42


<em>Area of the triangle</em> = 1/2 * B * H

B = TS = 3

H = RT =7

Area = 1/2 * 3 * 7

Area = 1/2 * 21

Area = 10.5


Total Area = 42 + 10.5 = 52.5 Both answers agree.

3 0
3 years ago
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