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Irina-Kira [14]
4 years ago
5

Change 12.39% to a decimal

Mathematics
2 answers:
tekilochka [14]4 years ago
6 0

To change a number to percent, move the
decimal point 2 places that way ==> .

To change a percent to a number, move the
decimal point 2 places this way <== .

               12.39%  =  0.1239 .

PSYCHO15rus [73]4 years ago
5 0

Answer:

The answar is 0.1239

Step-by-step explanation:

The percent sign tells un to divide 12.39 by a hundred(12.39/100). Divide 12.39 by hundred and you get 0.1239



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Write the equation y=-3x+3 in function notation using f(x) to denote the function.
Mumz [18]

The function notation form of the given equation; y = -3x +3 as in the task content is; f(x) = -3(x) +3.

<h3>What is the function notation form of the equation?</h3>

According to the task content, the equation given; y = -3x +3 is to be written in function notation.

Consequently, since the function expression given is linear in variable X, it follows that the required function notation is;

f(x) = -3x +3.

Read more on function notation;

brainly.com/question/25638609

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2 years ago
A student claims that 2i is the only imaginary root of a polynomial equation that has real coefficients. Explain the student's m
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Answer:

The Fundamental Theorem of Algebra assures that any polynomial  f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i

Step-by-step explanation:

1) This claim is mistaken.

2) The Fundamental Theorem of Algebra assures that any polynomial  f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i with real coefficients.

a_{0}x^{n}+a_{1}x^{2}+....a_{1}x+a_{0}

For example:

3) Every time a polynomial equation, like a quadratic equation which is an univariate polynomial one, has its discriminant following this rule:

\Delta < 0\\b^{2}-4*a*c

We'll have <em>n </em>different complex roots, not necessarily 2i.

For example:

Taking 3 polynomial equations with real coefficients, with

\Delta < 0

-4x^2-x-2=0 \Rightarrow S=\left \{ x'=-\frac{1}{8}-i\frac{\sqrt{31}}{8},\:x''=-\frac{1}{8}+i\frac{\sqrt{31}}{8} \right \}\\-x^2-x-8=0 \Rightarrow S=\left\{\quad x'=-\frac{1}{2}-i\frac{\sqrt{31}}{2},\:x''=-\frac{1}{2}+i\frac{\sqrt{31}}{2} \right \}\\x^2-x+30=0\Rightarrow S=\left \{ x'=\frac{1}{2}+i\frac{\sqrt{119}}{2},\:x''=\frac{1}{2}-i\frac{\sqrt{119}}{2} \right \}\\(...)

2.2) For other Polynomial equations with real coefficients we can see other complex roots ≠ 2i. In this one we have also -2i

x^5\:-\:x^4\:+\:x^3\:-\:x^2\:-\:12x\:+\:12=0 \Rightarrow S=\left \{ x_{1}=1,\:x_{2}=-\sqrt{3},\:x_{3}=\sqrt{3},\:x_{4}=2i,\:x_{5}=-2i \right \}\\

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3 years ago
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grin007 [14]

Answer:

x = 10, ∠ EHF = 110°

Step-by-step explanation:

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18x = 180 ( divide both sides by 18 )

x = 10

∠ EHF = 11x = 11(10) = 110°

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I believe the answer would be your first choice!
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(5 1/4) divieded by (-2 1/2)
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Answer:

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