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3 years ago

How did you get 7/20=0.35

Mathematics

2 answers:

Aloiza [94]3 years ago

5 0

7 / 20 is the same as 7 divided by 20

Simply put that in your calculator to get 0.35

Hope this helps!

Jet001 [13]3 years ago

4 0

$\frac{7}{20} = \frac{7 \times 5}{20 \times 5} = \frac{35}{100} = 0.35$

Hope that makes more sense to you as to why 7/20 = 0.35

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(x + 7)(x + 10) = what is the answer

ch4aika [34]

We can use FOIL to solve.

(x + 7)(x + 10)

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3 years ago

Find a point on the ellipsoid x2+y2+4z2=36x2+y2+4z2=36 where the tangent plane is perpendicular to the line with parametric equa

Anvisha [2.4K]

Answer:

A point on the ellipsoid is (-4,2,2) or (4,-2,-2)

Step-by-step explanation:

Given equation of ellipsoid f(x,y,z) : $x^2+y^2+4z^2=36$

Parametric equations:

x=-4t-1

y=2t+1

z=8t+3

Finding the gradient of function

$\nabla f(x,y,z)=\\\nabla f(x,y,z)=$

So, The directions vectors=(-4,2,8)

Now the line is perpendicular to plane when direction vector is parallel to the normal vector of line

$\nablaf(x,y,z)=(2x,2y,8z)=\lambda(-4,2,8)$

So, $2x=-4\lambda$

$\Rightarrow x=-2\lambda$

$2y=2\lambda\\\Rightarrow y=\lambda\\8z=8\lambda\\\Rightarrow z=\lambda$

Substitute the value of x , y and z in the ellipsoid equation

$(2\lambda)^2+(\lambda)^2+4(\lambda)^2=36\\9(\lambda)^2=36\\\lambda^2=4\\\lambda=\pm 2$

With $\lambda = 2$

x=-2(2)=-4

y=2

z=2

With $\lambda =- 2$

x=-2(-2)=4

y=-2

z=-2

Hence a point on the ellipsoid is (-4,2,2) or (4,-2,-2)

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3 years ago

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KATRIN_1 [288]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

A stack of cards is numbered 1 through 50 if a student selects a card what is the probability that the student will select a car

maw [93]

Answer:

The probability that the student will select a card that has both the same number in the ones place in the tens place is 0.08

Step-by-step explanation:

To solve this exercise we have to know that the probability is calculated by dividing the number of favorable events by the number of possible events.

f = favorable events

we will count how many numbers between 1 and 50 have the same number in the ones place in the tens place

11 ; 22 ; 33 ; 44

as we can see there are 4 numbers

f = 4

p = possible events

the number of possible events is given by the number of cards in the deck

p = 50

4/50 = 0.08

The probability that the student will select a card that has both the same number in the ones place in the tens place is 0.08

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3 years ago