An someone help me with this problem please?

What will happen to the size of the population in the long run?

Irina-Kira [14]

I'm assuming there's a chart, but if there isn't,

The population will continue to increase and decrease, as the population will grow until it's reached its carrying capacity, and then decrease because there aren't enough resources, and then increase, then decrease, etc.

7 0

3 years ago

1.) A man invested $600 at 8% per annum for 5 years. Calculate: a.) The simple interest payable b.) The total amount of money th

Bezzdna [24]

Answer:

Following are the solution to this question:

Step-by-step explanation:

Using formula:

$\text{Simple Interest} = \frac{P \times R \times T}{100} \\\\\text{ Total amount} = \text{principle}+ \text{Simple Interest}$

In question (1):

$Principle= \$ 600\\Rate = \ 8 \%\\Time= \ 5$

In point a:

$\to \frac{P \times R \times T}{100} \\\\\to \frac{(600 \times 8 \times 5)}{100}\\\\ \to 240$

In point b:

$\to amount = principle \ +\ simple \ interest$

$= 600 + 240 \\\\= 840$

In question (2):

$Principle= \$ 12,450\\Rate = \ 7.25 \%\\Time= \ 6$

In point a:

$\to \frac{P \times R \times T}{100} \\\\\to \frac{(12,450 \times 7.25 \times 6)}{100}\\\\ \to 5,415.75$

In point b:

$\to amount = principle \ +\ simple \ interest$

$= 12,450 + 5,415.75 \\\\= 17,865.75$

The 3 question is incomplete, that's why it can't be solved.

7 0

2 years ago

A random sample of 864 births in a state included 426 boys. Construct a 95% confidence interval estimate of the proportion of bo

oksian1 [2.3K]

Using the z-distribution, it is found that the 95% confidence interval is (0.46, 0.526), and it does not provide strong evidence against that belief.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

We have that a random sample of 864 births in a state included 426 boys, hence the parameters are given by:

$n = 864, \pi = \frac{426}{864} = 0.493$

Then, the bounds of the interval are given by:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.493 - 1.96\sqrt{\frac{0.493(0.507)}{864}} = 0.46$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.493 + 1.96\sqrt{\frac{0.493(0.507)}{864}} = 0.526$

The 95% confidence interval estimate of the proportion of boys in all births is (0.46, 0.526). Since the interval contains 0.506, it does not provide strong evidence against that belief.

More can be learned about the z-distribution at brainly.com/question/25890103

4 0

2 years ago

Find length,width and area<br><br>plus bonus<br><br>please show work

stira [4]

A square with the same perimeter as a rectangle will have larger area.

However, 42 is not divisible by 4, so we can do 10 by 11.

Length = 11, Width = 10, Area = 110

42 / 4 = 10.5

Length and Width = 10.5, Area = 110.25

3 0

2 years ago

Wait is it 43 or 41 pushups ?? I'm confused

SashulF [63]

Its 43 pushups cause the number of pushups are going up by 3

8 0

2 years ago

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