4x + 3y = 5...(1)
2x + 3y = 1...(2)
(2)*2:
4x+6y=2...(3)
(1)-(3):
4x+3y-(4x+6y)=5-2
4x+3y-4x-6y=3
-3y=3
y=-1
By sub. y=-1 in (2), we have
2x+3(-1)=1
2x-3=1
2x=4
x=2
The solution is x=2,y=-1
Answer:
what is the question
Step-by-step explanation:
i cant see any question marks
Answer:-2x^2(2-1)
Step-by-step explanation:
-4x^2 + 2x^2=-2x^2(2 - 1)
-2(x+5) OR 2(-x-5) I hope that helps if not please let me know!
You can easily test this if you know that (6, -10) corresponds to (X, Y). Knowing this, you can:
X = 6
Y = -10
you put this into your equation:
-10 = 3*6 - 8
calculate it:
-10 = 18 - 8
-10 = 10
This is not true of course, -10 is not equal to 10. Therefore, (6, -10) is not a solution of y = 3x-8 :)