Here ya go
53-bbb
54-c
55-ddd
56-eee
57-aaaga
if you have questions on the way I wrote it please ask
The measure of ∠ACB will be 110°
<u><em>Explanation</em></u>
According to the diagram below, and are the perpendicular bisectors of and respectively and they intersect side at points and respectively.
So, and
Now, <u>according to the postulate</u>, ΔAPE and ΔCPE are congruent each other. Also, ΔCFQ and ΔBFQ are congruent to each other.
That means, ∠PCE = ∠PAE and ∠FCQ = ∠FBQ
As ∠CPQ = 78° , so ∠PCE + ∠PAE = 78° or, ∠PCE = ° and as ∠CQP = 62° , so ∠FCQ + ∠FBQ = 62° or, ∠FCQ = °
Now, in triangle CPQ, ∠PCQ = 180°-(78° + 62°) = 180° - 140° = 40°
Thus, ∠ACB = ∠PCE + ∠PCQ + ∠FCQ = 39° + 40° + 31° = 110°
Answer:
80,000,000
Step-by-step explanation:
I think number 5 is A, the picture is kind of blurry.
3²×4²×3^4 = 3^6×4²
Number 6 is B.
In 5x+2
The +2 means two more and the 5x is five times a number,
therefore, it would be two more than five times a number