Answer:
10:12, 5:24, 9:13+1/3, 3:40, 20:6, 7:17+1/7
Step-by-step explanation:
You simply divide 120 by each of the numbers.
120/10=12, 120/5=24, 120/9=40/3, 120/3=40, 120/20=6, 120/7=12+1/7
Answer:
Given: BD is an altitude of △ABC .
Prove: sinA/a=sinC/c
Triangle ABC with an altitude BD where D is on side AC. Side AC is also labeled as small b. Side AB is also labeled as small c. Side BC is also labeled as small a. Altitude BD is labeled as small h.
Statement Reason
BD is an altitude of △ABC .
Given △ABD and △CBD are right triangles. (Definition of right triangle)
sinA=h/c and sinC=h/a
Cross multiplying, we have
csinA=h and asinC=h
(If a=b and a=c, then b=c)
csinA=asinC
csinA/ac=asinC/ac (Division Property of Equality)
sinA/a=sinC/c
This rule is known as the Sine Rule.
The answer is -5. -5 times 4 is -20, plus 9 is -11. -5 times 2 is -10, -1 is -11. -5 works.
Answer:
1.4
Step-by-step explanation:
12x+3x=15+6
15x=21
X=21/15
X=7/5 or 1.4
Answer: 100
5
Step-by-step explanation:
a) The mean of a normal distribution is also the median. Half the population will have values above the mean. Half of 200 is 100, so ...
... 100 students will have grades above 70%.
b) 84% is 14% above the mean. Each 7% is 1 standard deviation, so 14% is 2 standard deviations above the mean. The empirical rule tells you 95% of the population is within 2 standard deviations of the mean, so about 5% of students (10 students) got grades higher than 84% or lower than 56%. The normal distribution is symmetrical, so we expect about 5 students in each range.
... about 5 students will have grades above 84%.
