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love history [14]
2 years ago
15

Mrs. Drake gave her class the following problem to solve

Mathematics
1 answer:
Triss [41]2 years ago
7 0

Answer:

Kylie is incorect the aswer is supposed to be 32

Step-by-step explanation:

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Step by step please help answer.
sweet-ann [11.9K]

Answer:

(2) 2,640 ft

Step-by-step explanation:

I'm going to assume that in this question, you are walking 1 full circle around the reservoir. That would mean you need to calculate the circumference of the circular reservoir.

The circumference formula is:

C = ⫪d

C stands for Circumference

d stands for diameter

I will use 22/7 instead of pi, so the formula looks more like this:

C = (22/7)(d)

The diameter is 840 feet, so we will substitute the variable d with 840:

C = (22/7)(840)

You can plug this part into the calculator, but by hand, it'll look something like this:

(22/7)*840 = (22*840)/7

18,480/7 = 2.640

Hope it helps (●'◡'●)

5 0
3 years ago
On a Saturday, a library checked out 52 books. If 24 of the books were fiction , what is the ratio if non-fiction books to ficti
vekshin1
I would guess 28 to 24
4 0
2 years ago
Read 2 more answers
Find the following trigonometry values <br> cos (150*) = ? <br> sin (150*) = ?
melisa1 [442]

Answer:

See below in bold.

Step-by-step explanation:

cos 150 = - cos(180 - 150)

= - cos 30

= -√3/2.

sin 150

= sin (180 - 150

= sin 30

= 1/2.

4 0
3 years ago
Read 2 more answers
The length of a rectangle is represented by the polynomial 2x3 – 5x2 + 8 and the width is represented
Rom4ik [11]

1) the polynomial representing the area is

2x^4 + 6x^3 - 5x^2 -7x + 24

2) the constant term is

24

3) the polynomial is a 4th degree

4) if my guess is ryt... the LEADING coefficient is the coefficient of the highest degree of X ...i.e 2

8 0
3 years ago
Read 2 more answers
1.- What type of parabola is this?
xz_007 [3.2K]

Answer:

<u>Part 1</u>

<u>Sideways or "horizontal" parabola</u> with a horizontal axis of symmetry.

<u>Part 2</u>

The vertex is the turning point:  (-3, 1)

<u>Part 3</u>

Vertex form of a horizontal parabola:

x=a(y-k)^2+h    

where:

  • (h, k) is the vertex
  • a is some constant
    If a > 0 the parabola opens to the right.
    If a < 0 the parabola opens to the left.

Point on the curve:  (-1, 2)

Substituting the vertex and the found point into the formula and solving for a:

\implies -1=a(2-1)^2-3

\implies -1=a-3

\implies a=2

<u>Part 4</u>

Equation for the given parabola in vertex form:

x=2(y-1)^2-3

Equation in standard form:

x=2y^2-4y-1

4 0
1 year ago
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