Answer:
PQ = 3.58, and RQ = 10.4
Step-by-step explanation:
We are given the hypotenuse of the triangle, and an angle. Use sin and cos to solve.
Hypotenuse = 11,
Opposite side is PQ
Adjacent side is RQ
x = 19
Sin x = (opposite side)/(hypotenuse)
Cos x = (adjacent side)/(hypotenuse)
For PQ, this is the side opposite to the angle, so use sin,
Sin 19 = x/11
11(Sin 19) = x
3.58 = x (rounded to the nearest hundredth)
For RQ, this is the side adjacent to the angle, so use cos,
Cos 19 = x/11
11(Cos 19) = x
10.4 = x (rounded to the nearest hundredth)
Answer:
1/42
Step-by-step explanation:
1/7 ÷ 6/1
1 x 1 = 1
------------
7 x 6 = 42
1/42
already simplified to the fullest
hope that helps!
Answer:
-18
Step-by-step explanation:
((-3)2)3
First, you multiply -3 and 2 which equals -6
-3·2=-6
Then, you multiply -6 and 3 which equals -18
-6·3=-18
Answer:
5
Step-by-step explanation:
a=12 (height)
c=13 (hypotenous)
b=? (base)
By using Pythagoras theorm
We have, hypotenous sq=base sq+height sq
Let b =base SO, base sq=hypotenous Sq-height Sq
=>base Sq =13sq-12sq
Base Sq =169-144
Base Sq =25
Base =5 (shifting the sq)....
Hope it's helpful
Alright, so we start off my subtracting 4a from both sides, separating the x and getting 10-4a=2x. Next, we divide both sides by 2, getting that 5-2a=X
