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irina1246 [14]
2 years ago
15

Approximately 7.5 × 10^5 gallons of water flow over a waterfall each second. There are 8.6 × 10^4 seconds in one day. Approximat

ely how many gallons of water with flow over that waterfall in one day?
Mathematics
1 answer:
tino4ka555 [31]2 years ago
6 0

Answer:

6.45 \times  {10}^{10}

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Please help me find x<br> Need help fast!!
Bond [772]

Answer:

x = 100°

Step-by-step explanation:

p and q are parallel lines. Construct line 'l' parallel to p and q

a = 30°   {p// l  when parallel lines are intersected by transversal alternate interior angles are congruent}

c +110 = 180  {linear pair}

c = 180  - 110

c = 70°

b= c   {q // l  when parallel lines are intersected by transversal alternate interior angles are congruent}

b = 70°

x = a + b

x = 30° + 70°

x = 100°

6 0
3 years ago
How to differentiate y=x^n using the first principle. In this question, I cannot use the rule of differentiation. I have to do t
Zarrin [17]

By first principles, the derivative is

\displaystyle\lim_{h\to0}\frac{(x+h)^n-x^n}h

Use the binomial theorem to expand the numerator:

(x+h)^n=\displaystyle\sum_{i=0}^n\binom nix^{n-i}h^i=\binom n0x^n+\binom n1x^{n-1}h+\cdots+\binom nnh^n

(x+h)^n=x^n+nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n

where

\dbinom nk=\dfrac{n!}{k!(n-k)!}

The first term is eliminated, and the limit is

\displaystyle\lim_{h\to0}\frac{nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n}h

A power of h in every term of the numerator cancels with h in the denominator:

\displaystyle\lim_{h\to0}\left(nx^{n-1}+\dfrac{n(n-1)}2x^{n-2}h+\cdots+nxh^{n-2}+h^{n-1}\right)

Finally, each term containing h approaches 0 as h\to0, and the derivative is

y=x^n\implies y'=nx^{n-1}

4 0
3 years ago
How much money should a student place in a time deposit in a bank that pays 1.1% compounded annually so that he will have Php 20
STatiana [176]

Let us say that:<span>
   P = present value
   F = future value
    i = interest rate
   n = period

P = F / [ (1 + i ) ^n ]
P = 200000 / [ (1 + 0.011) ^6 ]
P = 187293.65

<span>Therefore the student must put up Php 187,293.65</span></span>

5 0
3 years ago
A 120-inch strip of metal 12 inches wide is to be made into a small open trough by bending up two sides on the long side, at rig
mezya [45]

Answer:

x= 3 inch should be turned up on each side

Step-by-step explanation:

Let the height of trough be x.

Width of trough be 12 - 2x.

and length of trough = 120 inch

Volume of trough, V = L×W×H = 120 × (12-2x) × x = 120x(12 - 2x)

For maximum volume, we find V' = 0

i.e 1440 -480x = 0

or  x = \frac{1440}{480}

or  x= 3

Hence x= 3 inch should be turned up on each side

3 0
3 years ago
How many liters of a 90% acid solution must be added to 6 liters of a 15% acid solution to obtain a 40% acid solution?
tatiyna

3 liters must be added

4 0
3 years ago
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